哪个PHP函数可以返回当前日期/时间?


当前回答

<?php
// Assuming today is March 10th, 2001, 5:16:18 pm, and that we are in the
// Mountain Standard Time (MST) Time Zone

$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day');     // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // it is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 17:16:18 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:18 m is month
$today = date("H:i:s");                         // 17:16:18
$today = date("Y-m-d H:i:s");                   // 2001-03-10 17:16:18 (the MySQL DATETIME format)
?>

其他回答

设置时区:

date_default_timezone_set('Asia/Calcutta');

然后调用日期函数

$date = date('Y-m-d H:i:s');

非常简单 echo $date = date('Y-m-d H:i:s');

您可以使用$_SERVER['REQUEST_TIME']变量(自PHP 5.1.0起可用)或time()函数来获取当前的Unix时间戳。

如果你想获得日期,如12-3-2016,分开每一天,月和年的值,然后复制粘贴以下代码:

$day = date("d");
$month = date("m");
$year = date("y");
print "date" . $day . "-" . $month . "-" . $year;

您的国家时区:支持的时区列表

date_default_timezone_set('Asia/Kolkata');

$dateYmd = date('Y-m-d');
echo "Current Year Month Day: $dateYmd";

本年月日:2022-01-03

$datehms = date('h:i:s');
echo "Current Hour Minute Second: $datehms";

当前小时分秒:11:05:38