在Flutter 2.0中，引入了Link小部件。使用这个小部件来启动网页，也可以导航到应用程序中的新屏幕。在使用它之前，你需要使用url_launcher包。

url_launcher: ^6.0.8

更多信息

Link(
              uri: Uri.parse('https://androidride.com'),
              //target: LinkTarget.self,
              builder: (context, followLink) {
                return RichText(
                  text: TextSpan(children: [
                    TextSpan(
                      text: 'Click here: ',
                      style: TextStyle(
                        fontSize: 20,
                        color: Colors.black,
                      ),
                    ),
                    TextSpan(
                      text: 'AndroidRide',
                      style: TextStyle(
                        color: Colors.blue,
                        decoration: TextDecoration.underline,
                        fontWeight: FontWeight.bold,
                        fontSize: 21,
                      ),
                      recognizer: TapGestureRecognizer()
                        ..onTap = followLink,
                    ),
                  ]),
                );
              }),
        ),
        SizedBox(
          height: 20,
        ),
        Link(
          uri: Uri.parse('/second'),
          builder: (context, followLink) {
            return InkWell(
              onTap: followLink,
              child: Text(
                'Go to Second Screen',
                style: TextStyle(
                  fontSize: 20,
                  color: Colors.blue,
                  decoration: TextDecoration.underline,
                ),
              ),
            );
          },
        ),

更新(Android >= 11):

iOS configuration: Open info.plist file and add: <key>LSApplicationQueriesSchemes</key> <array> <string>https</string> </array> Android configuration: Open AndroidManifest.xml file located in app/src/main and add the following at the root: <manifest xmlns:android="http://schemas.android.com/apk/res/android"> <!-- Add this query --> <queries> <intent> <action android:name="android.intent.action.VIEW" /> <data android:scheme="https" /> </intent> </queries> <application ... /> </manifest>

颤振代码:

简单地包装你的文本在一个手势探测器或InkWell和处理点击在onTap()使用url_launcher包。

InkWell(
  onTap: () => launchUrl(Uri.parse('https://www.google.com')),
  child: Text(
    'Click here',
    style: TextStyle(decoration: TextDecoration.underline, color: Colors.blue),
  ),
)

截图:

这是一整套的钥匙 https://pub.dev/packages/link_text

child: LinkText(
  'Hello check http://google.com',
  textStyle: ...,
),

对于这种复杂性，使用库更安全

优点:

作为单个参数接受整个字符串 解析链接并将其呈现为可点击的UI，与不可点击的文本内联 不需要复杂的RichText结构

只需将InkWell包装在Text小部件周围，并将UrlLauncher(来自服务库)提供给onTap属性。在下面使用UrlLauncher之前，将其安装为Flutter包。

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:url_launcher/url_launcher.dart';


void main() {
  runApp(new MyApp());
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new Scaffold(
        appBar: new AppBar(
          title: new Text('UrlLauncher'),
        ),
        body: new Center(
          child: new InkWell(
              child: new Text('Open Browser'),
              onTap: () => launch('https://docs.flutter.io/flutter/services/UrlLauncher-class.html')
          ),
        ),
      ),
    );
  }
}

您可以为Text小部件提供一个样式，使其看起来像一个链接。

更新

在研究了这个问题之后，我发现了一个不同的解决方案来实现你所要求的“在线”超链接。您可以使用RichText小部件与附带的textspan。

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:url_launcher/url_launcher.dart';

void main() {
  runApp(new MyApp());
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new Scaffold(
        appBar: new AppBar(
          title: new Text('UrlLauchner'),
        ),
        body: new Center(
          child: new RichText(
            text: new TextSpan(
              children: [
                new TextSpan(
                  text: 'This is no Link, ',
                  style: new TextStyle(color: Colors.black),
                ),
                new TextSpan(
                  text: 'but this is',
                  style: new TextStyle(color: Colors.blue),
                  recognizer: new TapGestureRecognizer()
                    ..onTap = () { launch('https://docs.flutter.io/flutter/services/UrlLauncher-class.html');
                  },
                ),
              ],
            ),
          ),
        ),
      ),
    );
  }
}

这样你就可以突出显示一个单词，并从中创建一个超链接;)

再添加一个简单而整洁的技巧，因为上面的技巧对于某些用例来说过于复杂。我用RichText - WidgetSpan, TextButton和URL启动包。只需根据您的需要修改下面的示例块。

结果:

代码:

class UserAgreementText extends StatelessWidget {
  const UserAgreementText({Key? key}) : super(key: key);

  @override
  Widget build(BuildContext context) {
    return Row(
      children: [
        Expanded(
          child: RichText(
            textAlign: TextAlign.center,
            text: TextSpan(
              text: 'By logging in, you accept our ',
              style: Theme.of(context).textTheme.bodySmall,
              children: const <InlineSpan>[
                WidgetSpan(
                  alignment: PlaceholderAlignment.baseline,
                  baseline: TextBaseline.alphabetic,
                  child: LinkButton(
                      urlLabel: "Terms and Conditions",
                      url: "https://example.com/terms-and-conditions"),
                ),
                TextSpan(
                  text: ' and ',
                ),
                WidgetSpan(
                  alignment: PlaceholderAlignment.baseline,
                  baseline: TextBaseline.alphabetic,
                  child: LinkButton(
                      urlLabel: "Privacy Policy",
                      url: "https://example.com/privacy-policy"),
                ),
              ],
            ),
          ),
        ),
      ],
    );
  }
}

link_button.dart

class LinkButton extends StatelessWidget {
  const LinkButton({Key? key, required this.urlLabel, required this.url})
      : super(key: key);

  final String urlLabel;
  final String url;

  Future<void> _launchUrl(String url) async {
    final Uri uri = Uri.parse(url);

    if (!await launchUrl(uri)) {
      throw 'Could not launch $uri';
    }
  }

  @override
  Widget build(BuildContext context) {
    return TextButton(
      style: TextButton.styleFrom(
        padding: EdgeInsets.zero,
        shape: RoundedRectangleBorder(
          borderRadius: BorderRadius.circular(0),
        ),
        tapTargetSize: MaterialTapTargetSize.shrinkWrap,
        visualDensity: VisualDensity.compact,
        minimumSize: const Size(0, 0),
        textStyle: Theme.of(context).textTheme.bodySmall,
      ),
      onPressed: () {
        _launchUrl(url);
      },
      child: Text(urlLabel),
    );
  }
}

注意:如果遇到与调用launchUrl相关的错误，请确保安装了URL启动器包，然后重新构建应用程序。

你可以使用链接文本https://pub.dev/packages/link_text 然后像这样使用它

 final String _text = 'Lorem ipsum https://flutter.dev\nhttps://pub.dev'; 
 @override
 Widget build(BuildContext context) {
 return Scaffold(
     body: Center(
      child: LinkText(
        text: _text,
        textAlign: TextAlign.center,
      ),
    ),
  );
}