我在MySQL数据库中有数据。我向用户发送一个URL,以获取他们的数据作为CSV文件。

我有链接的电子邮件,MySQL查询等覆盖。

当他们点击链接时,如何弹出从MySQL下载带有记录的CVS的窗口?

我已经有了所有能拿到唱片的资料。我只是不明白如何让PHP创建CSV文件,并让他们下载一个扩展名为. CSV的文件。


当前回答

公共函数actionExportnotificationresponselogdata() {

    $fileName = '/tmp/notificationresponselogs_' . date('d-m-Y-g-i-h') . '.csv';
    $f = fopen($fileName, 'w'); 
     fputs( $f, "\xEF\xBB\xBF" ); //for utf8 support in csv



        $csv_fields=array();
        $csv_fields[] = 'heading1';
        $csv_fields[] = 'heading2';
        $csv_fields[] = 'heading3';
        $csv_fields[] = 'heading4';
        $csv_fields[] = 'heading5';
        $csv_fields[] = 'heading6';
        $csv_fields[] = 'heading7';
        $csv_fields[] = 'heading8';
        fputcsv($f, $csv_fields);

    
$notification_log_arr = $notificationObj->getNotificationResponseForExport($params); //result from database

    if (count($notification_log_arr) > 0) {
        $serialNumber=1;
    foreach ($notification_log_arr AS $notifaction) {
            

            $fields = array();
            $fields['serialNumber']= $serialNumber  ;
            $fields['fld_1']= $notifaction['fld_1'] ;
            $fields['fld_2']= $notifaction['fld_2'] ;
            $fields['fld_3']= $notifaction['fld_3'] ;
            $fields['fld_4']= $notifaction['fld_4'] ;
            $fields['fld_5']= $notifaction['fld_5'] ;
            $fields['fld_6']= $notifaction['fld_6'] ; 
            $fields['fld_7']= $notifaction['fld_7'] ; 
           // print_r($fields); die;
            fputcsv($f, $fields,",");
        
            $serialNumber++;  }
            fclose($f);
            if (file_exists($fileName)) {
                
                header("Content-type: application/csv");
                header("Content-Disposition: attachment; filename="."exportlog".date("Y-m-d_H:i").".csv");
                header("Content-length: " . filesize($fileName));
                header("Pragma: no-cache"); 
                header("Expires: 0");
                readfile($fileName);
                unlink($fileName);
                exit;
            }
}

其他回答

除了上述内容,你可能还需要补充:

header("Content-Transfer-Encoding: UTF-8");

它在处理包含多种语言的文件时非常有用,比如人名或城市。

创建您的文件,然后用正确的标题返回对它的引用,以触发另存为-根据需要编辑以下内容。将您的CSV数据放入$csvdata。

$fname = 'myCSV.csv';
$fp = fopen($fname,'wb');
fwrite($fp,$csvdata);
fclose($fp);

header('Content-type: application/csv');
header("Content-Disposition: inline; filename=".$fname);
readfile($fname);

编写自己的CSV代码可能是浪费你的时间,只是使用一个包,如league/ CSV -它为你处理所有困难的事情,文档是很好的,它是非常稳定/可靠的:

http://csv.thephpleague.com/

你需要使用作曲家。如果你不知道什么是作曲家,我强烈建议你去看看:https://getcomposer.org/

〇简单的方法

$data = array (
    'aaa,bbb,ccc,dddd',
    '123,456,789',
    '"aaa","bbb"');

$fp = fopen('data.csv', 'wb');
foreach($data as $line){
    $val = explode(",",$line);
    fputcsv($fp, $val);
}
fclose($fp);

因此$data数组的每一行都将转到新创建的CSV文件的新行。它只适用于PHP 5及以后的版本。

而不是:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    $result.="{$row['email']},";
    $result.="\n";
    echo $result;
}

Use:

$query = "SELECT * FROM customers WHERE created>='{$start} 00:00:00'  AND created<='{$end} 23:59:59'   ORDER BY id";
$select_c = mysql_query($query) or die(mysql_error()); 

while ($row = mysql_fetch_array($select_c, MYSQL_ASSOC))
{
    echo implode(",", $row)."\n";
}