无法绑定多部分标识符

我在SO上看到过类似的错误，但我没有找到解决我的问题的方法。我有一个SQL查询像:

SELECT DISTINCT
        a.maxa ,
        b.mahuyen ,
        a.tenxa ,
        b.tenhuyen ,
        ISNULL(dkcd.tong, 0) AS tongdkcd
FROM    phuongxa a ,
        quanhuyen b
        LEFT OUTER JOIN ( SELECT    maxa ,
                                    COUNT(*) AS tong
                          FROM      khaosat
                          WHERE     CONVERT(DATETIME, ngaylap, 103) BETWEEN 'Sep 1 2011'
                                                              AND
                                                              'Sep 5 2011'
                          GROUP BY  maxa
                        ) AS dkcd ON dkcd.maxa = a.maxa
WHERE   a.maxa <> '99'
        AND LEFT(a.maxa, 2) = b.mahuyen
ORDER BY maxa;

当我执行这个查询时，错误结果是: 无法绑定多部分标识符“a.maxa”。为什么? P/s:如果我把查询分成2个单独的查询，它运行正常。

SELECT DISTINCT
        a.maxa ,
        b.mahuyen ,
        a.tenxa ,
        b.tenhuyen
FROM    phuongxa a ,
        quanhuyen b
WHERE   a.maxa <> '99'
        AND LEFT(a.maxa, 2) = b.mahuyen
ORDER BY maxa;

and

SELECT  maxa ,
        COUNT(*) AS tong
FROM    khaosat
WHERE   CONVERT(DATETIME, ngaylap, 103) BETWEEN 'Sep 1 2011'
                                        AND     'Sep 5 2011'
GROUP BY maxa;

当前回答

SELECT DISTINCT
        phuongxa.maxa ,
        quanhuyen.mahuyen ,
        phuongxa.tenxa ,
        quanhuyen.tenhuyen ,
        ISNULL(dkcd.tong, 0) AS tongdkcd
FROM    phuongxa ,
        quanhuyen
        LEFT OUTER JOIN ( SELECT    khaosat.maxa ,
                                    COUNT(*) AS tong
                          FROM      khaosat
                          WHERE     CONVERT(DATETIME, ngaylap, 103) BETWEEN 'Sep 1 2011'
                                                              AND
                                                              'Sep 5 2011'
                          GROUP BY  khaosat.maxa
                        ) AS dkcd ON dkcd.maxa = maxa
WHERE   phuongxa.maxa <> '99'
        AND LEFT(phuongxa.maxa, 2) = quanhuyen.mahuyen
ORDER BY maxa;

2017-04-27 21:32:40

其他回答

我的错误是使用了表中不存在的字段。

表1。Field1 =>不存在

表二。Field1 =>正确

更正表名。

我的错误是因为使用WITH

WITH RCTE AS (
   SELECT...
)
SELECT RCTE.Name, ...
FROM 
  RCTE INNER JOIN Customer
  ON RCTE.CustomerID = Customer.ID

当用于连接其他表时…

2017-08-14 14:43:16

相反，你可以尝试像这样连接桌子，

select 
  .... 
from 
   dkcd 
     right join 
                a
                  , b

这应该可以

2016-06-19 09:58:33

在我的例子中，问题原来是我给表设置的别名。对于SQL Server来说，“oa”似乎是不可接受的。

2018-04-02 16:35:48

SELECT DISTINCT
        phuongxa.maxa ,
        quanhuyen.mahuyen ,
        phuongxa.tenxa ,
        quanhuyen.tenhuyen ,
        ISNULL(dkcd.tong, 0) AS tongdkcd
FROM    phuongxa ,
        quanhuyen
        LEFT OUTER JOIN ( SELECT    khaosat.maxa ,
                                    COUNT(*) AS tong
                          FROM      khaosat
                          WHERE     CONVERT(DATETIME, ngaylap, 103) BETWEEN 'Sep 1 2011'
                                                              AND
                                                              'Sep 5 2011'
                          GROUP BY  khaosat.maxa
                        ) AS dkcd ON dkcd.maxa = maxa
WHERE   phuongxa.maxa <> '99'
        AND LEFT(phuongxa.maxa, 2) = quanhuyen.mahuyen
ORDER BY maxa;

2017-04-27 21:32:40

对我来说，问题是我愚蠢地调用一个DB函数没有空括号select [apo]。[GenerateNationalIdFrance]而不是select [apo].[GenerateNationalIdFrance]()…我花了几分钟才意识到这一点，但对大三学生来说值得一提:-)

2021-11-11 07:49:08

无法绑定多部分标识符

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