在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
在点击的时候保存最后一次点击的时间可以避免这个问题。
i.e.
private long mLastClickTime = 0;
...
// inside onCreate or so:
findViewById(R.id.button).setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// mis-clicking prevention, using threshold of 1000 ms
if (SystemClock.elapsedRealtime() - mLastClickTime < 1000){
return;
}
mLastClickTime = SystemClock.elapsedRealtime();
// do your magic here
}
}
其他回答
如果你在onClick()中进行计算密集型工作,则禁用按钮或设置不可点击是不够的,因为单击事件可以在禁用按钮之前排队。我写了一个实现OnClickListener的抽象基类,你可以重写,通过忽略任何排队点击来修复这个问题:
/**
* This class allows a single click and prevents multiple clicks on
* the same button in rapid succession. Setting unclickable is not enough
* because click events may still be queued up.
*
* Override onOneClick() to handle single clicks. Call reset() when you want to
* accept another click.
*/
public abstract class OnOneOffClickListener implements OnClickListener {
private boolean clickable = true;
/**
* Override onOneClick() instead.
*/
@Override
public final void onClick(View v) {
if (clickable) {
clickable = false;
onOneClick(v);
//reset(); // uncomment this line to reset automatically
}
}
/**
* Override this function to handle clicks.
* reset() must be called after each click for this function to be called
* again.
* @param v
*/
public abstract void onOneClick(View v);
/**
* Allows another click.
*/
public void reset() {
clickable = true;
}
}
用法与OnClickListener相同,但重写OnOneClick()代替:
OnOneOffClickListener clickListener = new OnOneOffClickListener() {
@Override
public void onOneClick(View v) {
// Do stuff
this.reset(); // or you can reset somewhere else with clickListener.reset();
}
};
myButton.setOnClickListener(clickListener);
当UI线程阻塞时,单击事件队列。对于按钮单击事件,请尽快将其更改为后台任务,以避免单击事件在彼此后面排队。
在activity类中声明一个volatile boolean或lock:
private volatile boolean saving = false;
创建一个onClickListener按钮,通过保存和启动一个后台任务来完成工作:
saveButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
if (!saving) {
saving = true;
new SaveAsyncTask().execute();
}
}
});
创建一个内部的SaveAsyncTask类来在后台完成工作:
class SaveAsyncTask extends AsyncTask {
@Override
protected Object doInBackground(Object[] objects) {
// Do something here, simulate a 3 second task
SystemClock.sleep(3000);
saving = false;
return null;
}
}
我的解决方案是尝试使用一个布尔变量:
public class Blocker {
private static final int DEFAULT_BLOCK_TIME = 1000;
private boolean mIsBlockClick;
/**
* Block any event occurs in 1000 millisecond to prevent spam action
* @return false if not in block state, otherwise return true.
*/
public boolean block(int blockInMillis) {
if (!mIsBlockClick) {
mIsBlockClick = true;
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
mIsBlockClick = false;
}
}, blockInMillis);
return false;
}
return true;
}
public boolean block() {
return block(DEFAULT_BLOCK_TIME);
}
}
并使用如下:
view.setOnClickListener(new View.OnClickListener() {
private Blocker mBlocker = new Blocker();
@Override
public void onClick(View v) {
if (!mBlocker.block(block-Time-In-Millis)) {
// do your action
}
}
});
更新:Kotlin解决方案,使用视图扩展
fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
var lastClickTime: Long = 0
this.setOnClickListener {
if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
lastClickTime = SystemClock.elapsedRealtime()
listener.onClick(this)
}
}
对我来说,只有记住时间戳并检查它(距离上次点击超过1秒)才有帮助。
对于任何使用数据绑定的用户:
@BindingAdapter("onClickWithDebounce")
fun onClickWithDebounce(view: View, listener: android.view.View.OnClickListener) {
view.setClickWithDebounce {
listener.onClick(view)
}
}
object LastClickTimeSingleton {
var lastClickTime: Long = 0
}
fun View.setClickWithDebounce(action: () -> Unit) {
setOnClickListener(object : View.OnClickListener {
override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - LastClickTimeSingleton.lastClickTime < 500L) return
else action()
LastClickTimeSingleton.lastClickTime = SystemClock.elapsedRealtime()
}
})
}
<androidx.appcompat.widget.AppCompatButton
..
android:text="@string/signup_signin"
app:onClickWithDebounce="@{() -> viewModel.onSignUpClicked()}"
... />
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