在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).

其他回答

在Java中有一个本地debounce click监听器

view.setOnClickListener(new DebouncedOnClickListener(1000) { //in milisecs
            @Override
            public void onDebouncedClick(View v) {
                //action
            }
        });

使用setEnabled(false)禁用按钮,直到用户可以安全地再次单击它。

你可以使用这种方法。通过使用后延迟,你可以照顾双击事件。

void debounceEffectForClick(查看视图){

    view.setClickable(false);

    view.postDelayed(new Runnable() {
        @Override
        public void run() {
            view.setClickable(true);

        }
    }, 500);
}

扩展的Kotlin方法:

fun View.setOneTimeClickListener(delayMillis: Long = 1000, block: () -> Unit) {
    setOnClickListener {
        this.isEnabled = false
        block()
        postDelayed({ isEnabled = true }, delayMillis)
    }

在代码中的用法:

someView.setOneTimeClickListener { someFun() }

delayMillis参数可用于设置按钮将被禁用的时间。

someView.setOneTimeClickListener(500) { someFun() }

Kotlin扩展,允许简洁的内联代码和变量双击等待时间

fun View.setDoubleClickListener(listener: View.OnClickListener, waitMillis : Long = 1000) {
    var lastClickTime = 0L
    setOnClickListener { view ->
        if (System.currentTimeMillis() > lastClickTime + waitMillis) {
            listener.onClick(view)
            lastClickTime = System.currentTimeMillis()
        }
    }
}

用法:

anyView.setNoDoubleClickListener(View.OnClickListener { v ->
    // do stuff
})

Or

anyView.setNoDoubleClickListener(View.OnClickListener { v ->
    // do stuff
}, 1500)