在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

我也遇到了类似的问题,我正在显示一些日期选择器和时间选择器,有时它会被点击2次。我用这个方法解决了这个问题:

long TIME = 1 * 1000;
@Override
public void onClick(final View v) {
v.setEnabled(false);
    
    new Handler().postDelayed(new Runnable() {

        @Override
        public void run() {
            v.setEnabled(true);
        }
    }, TIME);
}

你可以根据自己的需要改变时间。

其他回答

我的解决方案是

package com.shuai.view;

import android.os.SystemClock;
import android.view.View;

/**
 * 处理快速在某个控件上双击2次(或多次)会导致onClick被触发2次(或多次)的问题
 * 通过判断2次click事件的时间间隔进行过滤
 * 
 * 子类通过实现{@link #onSingleClick}响应click事件
 */
public abstract class OnSingleClickListener implements View.OnClickListener {
    /**
     * 最短click事件的时间间隔
     */
    private static final long MIN_CLICK_INTERVAL=600;
    /**
     * 上次click的时间
     */
    private long mLastClickTime;

    /**
     * click响应函数
     * @param v The view that was clicked.
     */
    public abstract void onSingleClick(View v);

    @Override
    public final void onClick(View v) {
        long currentClickTime=SystemClock.uptimeMillis();
        long elapsedTime=currentClickTime-mLastClickTime;
        //有可能2次连击,也有可能3连击,保证mLastClickTime记录的总是上次click的时间
        mLastClickTime=currentClickTime;

        if(elapsedTime<=MIN_CLICK_INTERVAL)
            return;

        onSingleClick(v);        
    }

}

用法类似于OnClickListener,但重写onSingleClick()代替:

mTextView.setOnClickListener(new OnSingleClickListener() {
            @Override
            public void onSingleClick(View v) {
                if (DEBUG)
                    Log.i("TAG", "onclick!");
            }
     };

似乎设置你的点击监听器在onResume和空他们在onPause也有技巧。

The Best and simple solution i found is 
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;

/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check 
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}

试试这个,它是有效的:

mButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

                mSlotLayout.setEnabled(false);

        //      do your work here

                Timer buttonTimer = new Timer();
                buttonTimer.schedule(new TimerTask() {

                    @Override
                    public void run() {

                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                mButton.setEnabled(true);
                            }
                        });
                    }
                }, 500); // delay button enable for 0.5 sec
    }
});

加上Jim的回答,代码可以变得更简洁:

fun View.setOnSingleClick(onClick: () -> Unit) {
    var lastClickTime = 0L
    setOnClickListener {
        if (currentTimeMillis() > lastClickTime + 750) onClick()
        lastClickTime = currentTimeMillis()
    } 
}

用法:

aView.setOnSingleClick {  }