严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?

堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。


当前回答

这是一个非常干净的CoffeeScript版本,你可以这样做:

Object::equals = (other) ->
  typeOf = Object::toString

  return false if typeOf.call(this) isnt typeOf.call(other)
  return `this == other` unless typeOf.call(other) is '[object Object]' or
                                typeOf.call(other) is '[object Array]'

  (return false unless this[key].equals other[key]) for key, value of this
  (return false if typeof this[key] is 'undefined') for key of other

  true

下面是测试:

  describe "equals", ->

    it "should consider two numbers to be equal", ->
      assert 5.equals(5)

    it "should consider two empty objects to be equal", ->
      assert {}.equals({})

    it "should consider two objects with one key to be equal", ->
      assert {a: "banana"}.equals {a: "banana"}

    it "should consider two objects with keys in different orders to be equal", ->
      assert {a: "banana", kendall: "garrus"}.equals {kendall: "garrus", a: "banana"}

    it "should consider two objects with nested objects to be equal", ->
      assert {a: {fruit: "banana"}}.equals {a: {fruit: "banana"}}

    it "should consider two objects with nested objects that are jumbled to be equal", ->
      assert {a: {a: "banana", kendall: "garrus"}}.equals {a: {kendall: "garrus", a: "banana"}}

    it "should consider two objects with arrays as values to be equal", ->
      assert {a: ["apple", "banana"]}.equals {a: ["apple", "banana"]}



    it "should not consider an object to be equal to null", ->
      assert !({a: "banana"}.equals null)

    it "should not consider two objects with different keys to be equal", ->
      assert !({a: "banana"}.equals {})

    it "should not consider two objects with different values to be equal", ->
      assert !({a: "banana"}.equals {a: "grapefruit"})

其他回答

这里有很多好的想法!这是我对深度相等的理解。我把它发布在github上,并围绕它写了一些测试。很难涵盖所有可能的情况,有时也没有必要这样做。

我介绍了NaN !== NaN以及循环依赖关系。

https://github.com/ryancat/simple-deep-equal/blob/master/index.js

这是一个非常干净的CoffeeScript版本,你可以这样做:

Object::equals = (other) ->
  typeOf = Object::toString

  return false if typeOf.call(this) isnt typeOf.call(other)
  return `this == other` unless typeOf.call(other) is '[object Object]' or
                                typeOf.call(other) is '[object Array]'

  (return false unless this[key].equals other[key]) for key, value of this
  (return false if typeof this[key] is 'undefined') for key of other

  true

下面是测试:

  describe "equals", ->

    it "should consider two numbers to be equal", ->
      assert 5.equals(5)

    it "should consider two empty objects to be equal", ->
      assert {}.equals({})

    it "should consider two objects with one key to be equal", ->
      assert {a: "banana"}.equals {a: "banana"}

    it "should consider two objects with keys in different orders to be equal", ->
      assert {a: "banana", kendall: "garrus"}.equals {kendall: "garrus", a: "banana"}

    it "should consider two objects with nested objects to be equal", ->
      assert {a: {fruit: "banana"}}.equals {a: {fruit: "banana"}}

    it "should consider two objects with nested objects that are jumbled to be equal", ->
      assert {a: {a: "banana", kendall: "garrus"}}.equals {a: {kendall: "garrus", a: "banana"}}

    it "should consider two objects with arrays as values to be equal", ->
      assert {a: ["apple", "banana"]}.equals {a: ["apple", "banana"]}



    it "should not consider an object to be equal to null", ->
      assert !({a: "banana"}.equals null)

    it "should not consider two objects with different keys to be equal", ->
      assert !({a: "banana"}.equals {})

    it "should not consider two objects with different values to be equal", ->
      assert !({a: "banana"}.equals {a: "grapefruit"})
const one={name:'mohit' , age:30};
//const two ={name:'mohit',age:30};
const two ={age:30,name:'mohit'};

function isEquivalent(a, b) {
// Create arrays of property names
var aProps = Object.getOwnPropertyNames(a);
var bProps = Object.getOwnPropertyNames(b);



// If number of properties is different,
// objects are not equivalent
if (aProps.length != bProps.length) {
    return false;
}

for (var i = 0; i < aProps.length; i++) {
    var propName = aProps[i];

    // If values of same property are not equal,
    // objects are not equivalent
    if (a[propName] !== b[propName]) {
        return false;
    }
}

// If we made it this far, objects
// are considered equivalent
return true;
}

console.log(isEquivalent(one,two))

为了比较简单的键/值对对象实例的键,我使用:

function compareKeys(r1, r2) {
    var nloops = 0, score = 0;
    for(k1 in r1) {
        for(k2 in r2) {
            nloops++;
            if(k1 == k2)
                score++; 
        }
    }
    return nloops == (score * score);
};

一旦比较了键,一个简单的for. in循环就足够了。

复杂度是O(N*N), N是键的个数。

我希望/猜测我定义的对象不会拥有超过1000个属性…

我知道这有点老了,但我想添加一个解决方案,我想出了这个问题。 我有一个对象,我想知道它的数据什么时候改变。类似于Object。我所做的是:

function checkObjects(obj,obj2){
   var values = [];
   var keys = [];
   keys = Object.keys(obj);
   keys.forEach(function(key){
      values.push(key);
   });
   var values2 = [];
   var keys2 = [];
   keys2 = Object.keys(obj2);
   keys2.forEach(function(key){
      values2.push(key);
   });
   return (values == values2 && keys == keys2)
}

这里可以复制并创建另一组数组来比较值和键。 这很简单,因为它们现在是数组,如果对象大小不同将返回false。