Xcode 8和Swift 3: 可以使用temparray . enumeration()枚举数组。

例子:

var someStrs = [String]()

someStrs.append("Apple")  
someStrs.append("Amazon")  
someStrs += ["Google"]    


for (index, item) in someStrs.enumerated()  
{  
        print("Value at index = \(index) is \(item)").  
}

控制台:

Value at index = 0 is Apple
Value at index = 1 is Amazon
Value at index = 2 is Google

在函数式编程中像这样使用. enumeration ():

list.enumerated().forEach { print($0.offset, $0.element) } 

从Swift 2开始，需要对集合调用enumerate函数，如下所示:

for (index, element) in list.enumerate() {
    print("Item \(index): \(element)")
}

你可以简单地使用循环枚举来得到你想要的结果:

斯威夫特2:

for (index, element) in elements.enumerate() {
    print("\(index): \(element)")
}

Swift 3和4:

for (index, element) in elements.enumerated() {
    print("\(index): \(element)")
}

或者你可以简单地执行一个for循环来得到相同的结果:

for index in 0..<elements.count {
    let element = elements[index]
    print("\(index): \(element)")
}

希望能有所帮助。

我们调用枚举函数来实现这个。就像

    for (index, element) in array.enumerate() {
     index is indexposition of array
     element is element of array 
   }

如果你出于某种原因想要一个更传统的查找循环，通过索引访问数组中的元素:

let xs = ["A", "B", "C", "D"]

for i in 0 ..< xs.count {
    print("\(i) - \(xs[i])")
}

输出:

0 - A
1 - B
2 - C
3 - D