我只想获取网站URL。不是从链接获取的URL。在页面加载时，我需要能够获取网站的完整、当前URL，并将其设置为一个变量，以便根据需要进行处理。
当前回答
您可以通过location.href获取当前页面的完整链接要获取当前控制器的链接，请使用：
location.href.substring(0, location.href.lastIndexOf('/'));
其他回答
location.origin+location.pathname+location.search+location.hash;
and
location.href
也一样。
获取当前页面URL:
window.location.href
你有多种方法可以做到这一点。
1:
location.href;
2:
document.URL;
3:
document.documentURI;
添加结果以供快速参考
窗口位置；
Location {href: "https://stackoverflow.com/questions/1034621/get-the-current-url-with-javascript",
ancestorOrigins: DOMStringList,
origin: "https://stackoverflow.com",
replace: ƒ, assign: ƒ, …}
文档位置
Location {href: "https://stackoverflow.com/questions/1034621/get-the-current-url-with-javascript",
ancestorOrigins: DOMStringList,
origin: "https://stackoverflow.com",
replace: ƒ, assign: ƒ
, …}
窗口位置路径名
"/questions/1034621/get-the-current-url-with-javascript"
窗口.location.href
"https://stackoverflow.com/questions/1034621/get-the-current-url-with-javascript"
位置主机名
"stackoverflow.com"
// http://127.0.0.1:8000/projects/page/2?name=jake&age=34
let url = new URL(window.location.href);
/*
hash: ""
host: "127.0.0.1:8000"
hostname: "127.0.0.1"
href: "http://127.0.0.1:8000/projects/page/2?username=jake&age=34"
origin: "http://127.0.0.1:8000"
password: ""
pathname: "/projects/page/2"
port: "8000"
protocol: "http:"
search: "?name=jake&age=34"
username: ""
*/
url.searchParams.get('name')
// jake
url.searchParams.get('age')
// 34
url.searchParams.get('gender')
// null
