我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?
当前回答
其他解决方案:
var dateAv = new Date();
var endTime = new Date(dateAv.getFullYear(), dateAv.getMonth(), dateAv.getDate(), dateAv.getHours(), dateAv.getMinutes() + 30);
其他回答
使用已知的现有库来处理处理时间计算所涉及的异常。我现在最喜欢的是moment.js。
<script src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.13.0/moment.js"></script>
<script>
var now = moment(); // get "now"
console.log(now.toDate()); // show original date
var thirty = moment(now).add(30,"minutes"); // clone "now" object and add 30 minutes, taking into account weirdness like crossing DST boundries or leap-days, -minutes, -seconds.
console.log(thirty.toDate()); // show new date
</script>
新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);
简单地,你可以在momnet库中使用这段代码:
console.log(moment(moment()).add(30,"minutes").format('MM/DD/YYYY hh:mm:ss'));
我总是创建7个函数,在JS中使用date: addSeconds, addMinutes, addHours, addDays, addWeeks, addMonths, addYears。
你可以在这里看到一个例子:http://jsfiddle.net/tiagoajacobi/YHA8x/
使用方法:
var now = new Date();
console.log(now.addMinutes(30));
console.log(now.addWeeks(3));
这些是函数:
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
return this;
};
Date.prototype.addMinutes = function(minutes) {
this.setMinutes(this.getMinutes() + minutes);
return this;
};
Date.prototype.addHours = function(hours) {
this.setHours(this.getHours() + hours);
return this;
};
Date.prototype.addDays = function(days) {
this.setDate(this.getDate() + days);
return this;
};
Date.prototype.addWeeks = function(weeks) {
this.addDays(weeks*7);
return this;
};
Date.prototype.addMonths = function (months) {
var dt = this.getDate();
this.setMonth(this.getMonth() + months);
var currDt = this.getDate();
if (dt !== currDt) {
this.addDays(-currDt);
}
return this;
};
Date.prototype.addYears = function(years) {
var dt = this.getDate();
this.setFullYear(this.getFullYear() + years);
var currDt = this.getDate();
if (dt !== currDt) {
this.addDays(-currDt);
}
return this;
};
也许像这样?
var d = new Date(); var v = new Date(); v.setMinutes (d.getMinutes () + 30); console.log (v)