是否可以在ES6类中创建私有属性?

举个例子。 如何阻止访问instance.property?

class Something {
  constructor(){
    this.property = "test";
  }
}

var instance = new Something();
console.log(instance.property); //=> "test"

当前回答

使用WeakMap可以在类中拥有私有方法。

根据MDN网络文档:

WeakMap对象是键/值对的集合,其中键仅为对象,值可以是任意值。 键中的对象引用是弱保存的,这意味着如果不再有对该对象的其他引用,则它们是垃圾收集(GC)的目标。

这是一个创建带有私有成员_items的Queue数据结构的例子,该成员_items包含一个数组。

const _items = new WeakMap();

class Queue {    
    constructor() {
        _items.set(this, []);
    }

    enqueue( item) {
        _items.get(this).push(item);
    }    

    get count() {
        return _items.get(this).length;        
    }

    peek() {
        const anArray = _items.get(this);
        if( anArray.length == 0)
            throw new Error('There are no items in array!');

        if( anArray.length > 0)
            return anArray[0];
    }

    dequeue() {        
        const anArray = _items.get(this);
        if( anArray.length == 0)
            throw new Error('There are no items in array!');

        if( anArray.length > 0)
            return anArray.splice(0, 1)[0];
    }    
}

使用的例子:

const c = new Queue();
c.enqueue("one");
c.enqueue("two");
c.enqueue("three");
c.enqueue("four");
c.enqueue("five");
console.log(c);

私有成员_items是隐藏的,不能在Queue对象的属性或方法中看到:

然而,Queue对象中的私有成员_items可以通过以下方式访问:

const anArray = _items.get(this);

其他回答

正如我们所知,ES6类不支持私有属性。

下面是我使用的方法(可能会有帮助)。基本上,我是在工厂内部包装一个类。

function Animal(name) {
    const privateData = 'NO experiments on animals have been done!';

    class Animal {
        constructor(_name) {
            this.name = _name;
        }
        getName() {
            return this.name
        }
        getDisclamer() {
            return `${privateData} Including ${this.name}`
        }
    }
    return new Animal(name)
}

我是一个初学者,所以很高兴听到这是一个坏的方法。

来这个派对很晚,但我在搜索中碰到了OP问题,所以… 是的,您可以通过将类声明包装在闭包中来拥有私有属性

这里有一个我如何在这个代码依赖中拥有私有方法的例子。在下面的代码片段中,Subscribable类有两个“私有”函数process和processCallbacks。任何属性都可以以这种方式添加,并且通过使用闭包将它们保持为私有。如果关注点被很好地分离,并且Javascript不需要通过添加更多的语法而变得臃肿,当闭包整齐地完成工作时,隐私是一个罕见的需求。

const Subscribable = (function(){

  const process = (self, eventName, args) => {
    self.processing.set(eventName, setTimeout(() => processCallbacks(self, eventName, args)))};

  const processCallbacks = (self, eventName, args) => {
    if (self.callingBack.get(eventName).length > 0){
      const [nextCallback, ...callingBack] = self.callingBack.get(eventName);
      self.callingBack.set(eventName, callingBack);
      process(self, eventName, args);
      nextCallback(...args)}
    else {
      delete self.processing.delete(eventName)}};

  return class {
    constructor(){
      this.callingBack = new Map();
      this.processing = new Map();
      this.toCallbacks = new Map()}

    subscribe(eventName, callback){
      const callbacks = this.unsubscribe(eventName, callback);
      this.toCallbacks.set(eventName,  [...callbacks, callback]);
      return () => this.unsubscribe(eventName, callback)}  // callable to unsubscribe for convenience

    unsubscribe(eventName, callback){
      let callbacks = this.toCallbacks.get(eventName) || [];
      callbacks = callbacks.filter(subscribedCallback => subscribedCallback !== callback);
      if (callbacks.length > 0) {
        this.toCallbacks.set(eventName, callbacks)}
      else {
        this.toCallbacks.delete(eventName)}
      return callbacks}

    emit(eventName, ...args){
      this.callingBack.set(eventName, this.toCallbacks.get(eventName) || []);
      if (!this.processing.has(eventName)){
        process(this, eventName, args)}}}})();

我喜欢这种方法,因为它很好地分离了关注点,并保持了真正的私密性。唯一的缺点是需要使用'self'(或类似的东西)在私有内容中引用'this'。

就我个人而言,我喜欢绑定操作符::的建议,然后将其与@d13提到的解决方案结合起来,但现在坚持使用@d13的答案,在这里您为类使用export关键字,并将私有函数放在模块中。

还有一个棘手的解决方案,这里没有提到,下面是更实用的方法,将允许它在类中拥有所有的私有道具/方法。

Private.js

export const get = state => key => state[key];
export const set = state => (key,value) => { state[key] = value; }

. js

import { get, set } from './utils/Private'
export default class Test {
  constructor(initialState = {}) {
    const _set = this.set = set(initialState);
    const _get = this.get = get(initialState);

    this.set('privateMethod', () => _get('propValue'));
  }

  showProp() {
    return this.get('privateMethod')();
  }
}

let one = new Test({ propValue: 5});
let two = new Test({ propValue: 8});
two.showProp(); // 8
one.showProp(); // 5

请对此提出意见。

Yes totally can, and pretty easily too. This is done by exposing your private variables and functions by returning the prototype object graph in the constructor. This is nothing new, but take a bit of js foo to understand the elegance of it. This way does not use global scoped, or weakmaps. It is a form of reflection built into the language. Depending on how you leverage this; one can either force an exception which interrupts the call stack, or bury the exception as an undefined. This is demonstarted below, and can read more about these features here

class Clazz { constructor() { var _level = 1 function _private(x) { return _level * x; } return { level: _level, public: this.private, public2: function(x) { return _private(x); }, public3: function(x) { return _private(x) * this.public(x); }, }; } private(x) { return x * x; } } var clazz = new Clazz(); console.log(clazz._level); //undefined console.log(clazz._private); // undefined console.log(clazz.level); // 1 console.log(clazz.public(1)); //1 console.log(clazz.public2(2)); //2 console.log(clazz.public3(3)); //27 console.log(clazz.private(0)); //error

更新:看别人的回答,这个已经过时了。

简单的回答,不,ES6类不支持私有属性。

但是你可以模仿这种行为,不将新属性附加到对象,而是将它们保存在类构造函数中,并使用getter和setter来获取隐藏的属性。注意,在类的每个新实例上重新定义getter和setter。

ES6

class Person {
    constructor(name) {
        var _name = name
        this.setName = function(name) { _name = name; }
        this.getName = function() { return _name; }
    }
}

ES5

function Person(name) {
    var _name = name
    this.setName = function(name) { _name = name; }
    this.getName = function() { return _name; }
}