我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

下面是我用于可达性检查的Kotlin版本,

芬兰湾的科特林MyReachability

object MyReachability {

    private val REACHABILITY_SERVER = "http://google.com" // can be any URL you want

    private fun hasNetworkAvailable(context: Context): Boolean {
        val service = Context.CONNECTIVITY_SERVICE
        val manager = context.getSystemService(service) as ConnectivityManager?
        val network = manager?.activeNetworkInfo
        Log.d(classTag, "hasNetworkAvailable: ${(network != null)}")
        return (network != null)
    }

    fun hasInternetConnected(context: Context): Boolean {
        if (hasNetworkAvailable(context)) {
            try {
                val connection = URL(REACHABILITY_SERVER).openConnection() as HttpURLConnection
                connection.setRequestProperty("User-Agent", "Test")
                connection.setRequestProperty("Connection", "close")
                connection.connectTimeout = 1500
                connection.connect()
                Log.d(classTag, "hasInternetConnected: ${(connection.responseCode == 200)}")
                return (connection.responseCode == 200)
            } catch (e: IOException) {
                Log.e(classTag, "Error checking internet connection", e)
            }
        } else {
            Log.w(classTag, "No network available!")
        }
        Log.d(classTag, "hasInternetConnected: false")
        return false
    }
}

您甚至可以根据策略和限制将REACHABILITY_SERVER作为参数传递,例如,当您在中国时,您可以检查https://baidu.com而不是https://google.com。

调用示例中,

val webLoaderThread = Thread {
   if (MyReachability.hasInternetConnected(this)){
       runOnUiThread {
           //mWebView.loadUrl(LANDING_SERVER) // connected
       }
   } else {
       runOnUiThread {
           //showDialogNoNetwork() // not connected
       }
   }
}
webLoaderThread.start()

安卓系统权限

不要忘记将以下权限添加到你的AndroidManifest.xml中

<uses-permission android:name="android.permission.INTERNET"/>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>

其他回答

有不止一种方法

第一,最短但效率低的方法

只需要网络状态权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

然后这个方法,

 public boolean activeNetwork () {
        ConnectivityManager cm =
                (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);

        NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
        boolean isConnected = activeNetwork != null &&
                activeNetwork.isConnected();

        return isConnected;

    }

正如在回答中所看到的ConnectivityManager是一个解决方案,我只是在一个方法中添加了它,这是一个简化的方法 ConnectivityManager返回true,如果有网络访问而不是互联网访问,这意味着如果你的WiFi连接到路由器,但路由器没有互联网,它返回true,它检查连接可用性

二、高效的方式

需要网络状态和Internet权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />

然后这门课,

 public class CheckInternetAsyncTask extends AsyncTask<Void, Integer, Boolean> {

        private Context context;

        public CheckInternetAsyncTask(Context context) {
            this.context = context;
        }

        @Override
        protected Boolean doInBackground(Void... params) {

            ConnectivityManager cm =
                    (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);

            assert cm != null;
            NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
            boolean isConnected = activeNetwork != null &&
                    activeNetwork.isConnected();


            if (isConnected) {
                try {
                    HttpURLConnection urlc = (HttpURLConnection)
                            (new URL("http://clients3.google.com/generate_204")
                                    .openConnection());
                    urlc.setRequestProperty("User-Agent", "Android");
                    urlc.setRequestProperty("Connection", "close");
                    urlc.setConnectTimeout(1500);
                    urlc.connect();
                    if (urlc.getResponseCode() == 204 &&
                            urlc.getContentLength() == 0)
                        return true;

                } catch (IOException e) {
                    Log.e("TAG", "Error checking internet connection", e);
                    return false;
                }
            } else {
                Log.d("TAG", "No network available!");
                return false;
            }


            return null;
        }

        @Override
        protected void onPostExecute(Boolean result) {
            super.onPostExecute(result);
            Log.d("TAG", "result" + result);

            if(result){
                // do ur code
            }

        }


    }

叫CheckInternetAsyncTask

new CheckInternetAsyncTask(getApplicationContext()).execute();

部分解释:-

you have to check Internet on AsyncTask, otherwise it can throw android.os.NetworkOnMainThreadException in some cases ConnectivityManager used to check the network access if true sends request (Ping) Request send to http://clients3.google.com/generate_204, This well-known URL is known to return an empty page with an HTTP status 204 this is faster and more efficient than http://www.google.com , read this. if you have website it's preferred to put you website instead of google, only if you use it within the app Timeout can be changed range (20ms -> 2000ms), 1500ms is commonly used

如果设备处于飞行模式(或者假设在没有可用网络的其他情况下),cm.getActiveNetworkInfo()将为空,因此您需要添加一个空检查。

修改(Eddie的解决方案)如下:

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    return netInfo != null && netInfo.isConnectedOrConnecting();
}

在AndroidManifest.xml中添加以下权限:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

还有一点,如果你在给定的时间点绝对需要一个网络连接,那么使用netInfo.isConnected()而不是netInfo.isConnectedOrConnecting可能会更好。不过,我想这取决于个人用例。

从以下链接找到并修改(!):

在你的manifest文件中至少添加:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

如果您正在访问它,您可能已经拥有INTERNET权限。那么一个允许测试连通性的布尔函数是:

private boolean checkInternetConnection() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    // test for connection
    if (cm.getActiveNetworkInfo() != null
            && cm.getActiveNetworkInfo().isAvailable()
            && cm.getActiveNetworkInfo().isConnected()) {
        return true;
    } else {
        Log.v(TAG, "Internet Connection Not Present");
        return false;
    }
}

网络连接/互联网接入

isConnectedOrConnecting()(在大多数回答中使用)检查任何网络连接 要了解这些网络是否有internet接入,请使用以下方法之一

A) Ping服务器(简单)

// ICMP 
public boolean isOnline() {
    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int     exitValue = ipProcess.waitFor();
        return (exitValue == 0);
    }
    catch (IOException e)          { e.printStackTrace(); }
    catch (InterruptedException e) { e.printStackTrace(); }

    return false;
}

+可以在主线程上运行

在一些旧设备上不能工作(Galays S3等),如果没有网络,它会阻塞一段时间。

B)连接到Internet上的Socket(高级)

// TCP/HTTP/DNS (depending on the port, 53=DNS, 80=HTTP, etc.)
public boolean isOnline() {
    try {
        int timeoutMs = 1500;
        Socket sock = new Socket();
        SocketAddress sockaddr = new InetSocketAddress("8.8.8.8", 53);

        sock.connect(sockaddr, timeoutMs);
        sock.close();

        return true;
    } catch (IOException e) { return false; }
}

+非常快(任何一种方式),适用于所有设备,非常可靠

-不能在UI线程上运行

这工作非常可靠,在每个设备上,非常快。它需要在一个单独的任务中运行(例如ScheduledExecutorService或AsyncTask)。

可能的问题

Is it really fast enough? Yes, very fast ;-) Is there no reliable way to check internet, other than testing something on the internet? Not as far as I know, but let me know, and I will edit my answer. What if the DNS is down? Google DNS (e.g. 8.8.8.8) is the largest public DNS in the world. As of 2018 it handled over a trillion queries a day [1]. Let 's just say, your app would probably not be the talk of the day. Which permissions are required? <uses-permission android:name="android.permission.INTERNET" /> Just internet access - surprise ^^ (Btw have you ever thought about, how some of the methods suggested here could even have a remote glue about internet access, without this permission?)

 

额外:一次性RxJava/RxAndroid示例(Kotlin)

fun hasInternetConnection(): Single<Boolean> {
  return Single.fromCallable {
    try {
      // Connect to Google DNS to check for connection
      val timeoutMs = 1500
      val socket = Socket()
      val socketAddress = InetSocketAddress("8.8.8.8", 53)
    
      socket.connect(socketAddress, timeoutMs)
      socket.close()
  
      true
    } catch (e: IOException) {
      false
    }
  }
  .subscribeOn(Schedulers.io())
  .observeOn(AndroidSchedulers.mainThread())
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe { hasInternet -> /* do something */}

额外:一次性RxJava/RxAndroid示例(Java)

public static Single<Boolean> hasInternetConnection() {
    return Single.fromCallable(() -> {
        try {
            // Connect to Google DNS to check for connection
            int timeoutMs = 1500;
            Socket socket = new Socket();
            InetSocketAddress socketAddress = new InetSocketAddress("8.8.8.8", 53);

            socket.connect(socketAddress, timeoutMs);
            socket.close();

            return true;
        } catch (IOException e) {
            return false;
        }
    }).subscribeOn(Schedulers.io()).observeOn(AndroidSchedulers.mainThread());
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe((hasInternet) -> {
        if(hasInternet) {

        }else {

        }
    });

额外:一次性AsyncTask示例

注意:这是如何执行请求的另一个示例。然而,由于AsyncTask已弃用,它应该被你的应用程序的线程调度,Kotlin协程,Rx,…

class InternetCheck extends AsyncTask<Void,Void,Boolean> {

    private Consumer mConsumer;
    public  interface Consumer { void accept(Boolean internet); }

    public  InternetCheck(Consumer consumer) { mConsumer = consumer; execute(); }

    @Override protected Boolean doInBackground(Void... voids) { try {
        Socket sock = new Socket();
        sock.connect(new InetSocketAddress("8.8.8.8", 53), 1500);
        sock.close();
        return true;
    } catch (IOException e) { return false; } }

    @Override protected void onPostExecute(Boolean internet) { mConsumer.accept(internet); }
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    new InternetCheck(internet -> { /* do something with boolean response */ });

移动设备上的一个重要用例是确保存在实际连接。当移动用户使用“专属门户”进入Wifi网络时,这是一个常见的问题,他们需要在其中登录。我在后台使用这个阻塞功能来确保连接存在。

/*
 * Not Thread safe. Blocking thread. Returns true if it
 * can connect to URL, false and exception is logged.
 */
public boolean checkConnectionHttps(String url){
    boolean responded = false;
    HttpGet requestTest = new HttpGet(url);
    HttpParams params = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(params, 3000);
    HttpConnectionParams.setSoTimeout(params, 5000);
    DefaultHttpClient client = new DefaultHttpClient(params);
    try {
        client.execute(requestTest);
        responded = true;
    } catch (ClientProtocolException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
    } catch (IOException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
        e.printStackTrace();
    }
    return responded;
}