回答没有外部库的简单进度条

import time, sys

def progress(size):
    for item in range(size):
        if(item==0):
            print("[",end="")

        elif(item==size-1):
            print("]",end="\n")

        else:
            #main work goes here
            time.sleep(0.1)
            print("%",end="")
            sys.stdout.flush()

progress(50)

上面的建议非常好，但我认为大多数人只是想要一个现成的解决方案，不依赖于外部包，但也是可重用的。

我得到了上面所有的优点，并把它做成了一个函数，以及一个测试用例。

要使用它，只需复制“def update_progress(progress)”下面的行，而不是测试脚本。不要忘记导入sys。在需要显示或更新进度条时调用此函数。

这是通过直接向控制台发送“\r”符号来将光标移回起始位置。python中的"print"不能识别上述符号，因此我们需要'sys'

import time, sys

# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
    barLength = 10 # Modify this to change the length of the progress bar
    status = ""
    if isinstance(progress, int):
        progress = float(progress)
    if not isinstance(progress, float):
        progress = 0
        status = "error: progress var must be float\r\n"
    if progress < 0:
        progress = 0
        status = "Halt...\r\n"
    if progress >= 1:
        progress = 1
        status = "Done...\r\n"
    block = int(round(barLength*progress))
    text = "\rPercent: [{0}] {1}% {2}".format( "#"*block + "-"*(barLength-block), progress*100, status)
    sys.stdout.write(text)
    sys.stdout.flush()


# update_progress test script
print "progress : 'hello'"
update_progress("hello")
time.sleep(1)

print "progress : 3"
update_progress(3)
time.sleep(1)

print "progress : [23]"
update_progress([23])
time.sleep(1)

print ""
print "progress : -10"
update_progress(-10)
time.sleep(2)

print ""
print "progress : 10"
update_progress(10)
time.sleep(2)

print ""
print "progress : 0->1"
for i in range(101):
    time.sleep(0.1)
    update_progress(i/100.0)

print ""
print "Test completed"
time.sleep(10)

这是测试脚本显示的结果(最后一个进度条是动画):

progress : 'hello'
Percent: [----------] 0% error: progress var must be float
progress : 3
Percent: [##########] 100% Done...
progress : [23]
Percent: [----------] 0% error: progress var must be float

progress : -10
Percent: [----------] 0% Halt...

progress : 10
Percent: [##########] 100% Done...

progress : 0->1
Percent: [##########] 100% Done...
Test completed

我真的很喜欢python-progressbar，因为它使用起来非常简单。

对于最简单的情况，它是:

import progressbar
import time

progress = progressbar.ProgressBar()
for i in progress(range(80)):
    time.sleep(0.01)

外观可以自定义，它可以显示估计的剩余时间。举个例子，使用与上面相同的代码，但是包含:

progress = progressbar.ProgressBar(widgets=[progressbar.Bar('=', '[', ']'), ' ',
                                            progressbar.Percentage(), ' ',
                                            progressbar.ETA()])

一个非常简单的方法:

def progbar(count: int) -> None:
    for i in range(count):
        print(f"[{i*'#'}{(count-1-i)*' '}] - {i+1}/{count}", end="\r")
        yield i
    print('\n')

以及用法:

from time import sleep

for i in progbar(10):
    sleep(0.2) #whatever task you need to do

这是创建进度条的简单方法

import time,sys
toolbar_width = 50
# setting up toolbar [-------------------------------------]
sys.stdout.write("[%s]"%(("-")*toolbar_width))
sys.stdout.flush()
# each hash represents 2 % of the progress
for i in range(toolbar_width):
    sys.stdout.write("\r") # return to start of line
    sys.stdout.flush()
    sys.stdout.write("[")#Overwrite over the existing text from the start 
    sys.stdout.write("#"*(i+1))# number of # denotes the progress completed 
    sys.stdout.flush()
    time.sleep(0.1)

这里有一个简单的解决方案!

void = '-'
fill = '#'
count = 100/length
increaseCount = 0
for i in range(length):
    print('['+(fill*i)+(void*(length-i))+'] '+str(int(increaseCount))+'%',end='\r')
    increaseCount += count
    time.sleep(0.1)
print('['+(fill*(i+1))+(void*(length-(i+1)))+'] '+str(int(increaseCount))+'%',end='\n')

注意:如果需要，可以修改fill和“void”字符。

加载条(图片)