您可以在任何色相背景上有任何色相文本，并确保它是易读的。我一直都这么做。在Javascript中有一个关于可读的彩色文本的公式- STW* 正如它在那个链接上所说的那样，这个公式是逆伽马调整计算的变化，尽管IMHO更易于管理。 该链接右侧的菜单及其相关页面使用随机生成的颜色作为文本和背景，始终清晰可辨。所以，是的，显然这是可以做到的，没有问题。

丑陋的Python，如果你不想写它:)

'''
Input a string without hash sign of RGB hex digits to compute
complementary contrasting color such as for fonts
'''
def contrasting_text_color(hex_str):
    (r, g, b) = (hex_str[:2], hex_str[2:4], hex_str[4:])
    return '000' if 1 - (int(r, 16) * 0.299 + int(g, 16) * 0.587 + int(b, 16) * 0.114) / 255 < 0.5 else 'fff'

作为Kotlin / Android扩展:

fun Int.getContrastColor(): Int {
    // Counting the perceptive luminance - human eye favors green color...
    val a = 1 - (0.299 * Color.red(this) + 0.587 * Color.green(this) + 0.114 * Color.blue(this)) / 255
    return if (a < 0.5) Color.BLACK else Color.WHITE
}

我本想对@MichaelChirico的回答发表评论，但我没有足够的声誉。这里有一个在R中返回颜色的例子:

get_text_colour <- function(
    background_colour,
    light_text_colour = 'white',
    dark_text_colour = 'black',
    threshold = 0.5
) {

    background_luminance <- c( 
        c( .299, .587, .114 ) %*% col2rgb( background_colour ) / 255
    )

    return(
        ifelse(
            background_luminance < threshold,
            light_text_colour,
            dark_text_colour
        )
    )
}

> get_text_colour( background_colour = 'blue' )
[1] "white"

> get_text_colour( background_colour = c( 'blue', 'yellow', 'pink' ) )
[1] "white" "black" "black"

> get_text_colour( background_colour = c('black', 'white', '#236FAB', 'darkred', '#01F11F') )
[1] "white" "black" "white" "white" "black"

Swift 4示例:

extension UIColor {

    var isLight: Bool {
        let components = cgColor.components

        let firstComponent = ((components?[0]) ?? 0) * 299
        let secondComponent = ((components?[1]) ?? 0) * 587
        let thirdComponent = ((components?[2]) ?? 0) * 114
        let brightness = (firstComponent + secondComponent + thirdComponent) / 1000

        return !(brightness < 0.6)
    }

}

更新-发现0.6是一个更好的查询测试平台

我对Gacek回答的快速实现:

func contrastColor(color: UIColor) -> UIColor {
    var d = CGFloat(0)

    var r = CGFloat(0)
    var g = CGFloat(0)
    var b = CGFloat(0)
    var a = CGFloat(0)

    color.getRed(&r, green: &g, blue: &b, alpha: &a)

    // Counting the perceptive luminance - human eye favors green color...
    let luminance = 1 - ((0.299 * r) + (0.587 * g) + (0.114 * b))

    if luminance < 0.5 {
        d = CGFloat(0) // bright colors - black font
    } else {
        d = CGFloat(1) // dark colors - white font
    }

    return UIColor( red: d, green: d, blue: d, alpha: a)
}