Xcode不接受与普通字符串一起添加的可选字符串。我写了这个扩展来解决这个问题:

extension String {
    mutating func addString(str: String) {
        self = self + str
    }
}

然后你可以这样称呼它:

var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1.addString(str2)
println(str1) //hi my name is

然而，你现在也可以这样做:

var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1! += str2

斯威夫特4.2

你也可以使用扩展:

extension Array where Element == String? {
    func compactConcate(separator: String) -> String {
        return self.compactMap {
            if let unwrappedString = $0,
               unwrappedString.isEmpty {
                return nil
            } else {
                return $0
            }
        }
        .joined(separator: separator)
    }
}

Use:

label.text = [m.firstName, m.lastName].compactConcate(separator: " ")

结果:

"The Man"
"The"
"Man"

var language = "Swift" 
var resultStr = "\(language) is a new programming language"

非常简单:

let StringA = "Hello"
let StringB = "World"
let ResultString = "\(StringA)\(StringB)"
println("Concatenated result = \(ResultString)")

我刚从Objective-C切换到Swift(4)，我发现我经常使用:

let allWords = String(format:"%@ %@ %@",message.body!, message.subject!, message.senderName!)

斯威夫特5

你可以使用附加API来实现它。这将返回一个通过将给定字符串追加到接收器而生成的新字符串。

API详情:此处

Use:

var text = "Hello"
text = text.appending(" Namaste")

结果:

Hello
Hello Namaste