对于>= iOS8:(简化@EliBud的回答)。

#define APP_STORE_ID 1108885113

- (void)rateApp{
    static NSString *const iOSAppStoreURLFormat = @"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=%d";

    NSURL *appStoreURL = [NSURL URLWithString:[NSString stringWithFormat:iOSAppStoreURLFormat, APP_STORE_ID]];

    if ([[UIApplication sharedApplication] canOpenURL:appStoreURL]) {
        [[UIApplication sharedApplication] openURL:appStoreURL];
    }
}

NSString *url = [NSString stringWithFormat:@"https://itunes.apple.com/us/app/kidsworld/id906660185?ls=1&mt=8"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];

以上方法都是正确的，但是现在使用SKStoreProductViewController可以带来更好的用户体验。要使用它，你需要做以下工作:

implement SKStoreProductViewControllerDelegate protocol in your app delegate add required productViewControllerDidFinish method: - (void)productViewControllerDidFinish:(SKStoreProductViewController *)viewController { [viewController dismissViewControllerAnimated: YES completion: nil]; } Check if SKStoreProductViewController class is available and either show it or switch to the App Store: extern NSString* cAppleID; // must be defined somewhere... if ([SKStoreProductViewController class] != nil) { SKStoreProductViewController* skpvc = [[SKStoreProductViewController new] autorelease]; skpvc.delegate = self; NSDictionary* dict = [NSDictionary dictionaryWithObject: cAppleID forKey: SKStoreProductParameterITunesItemIdentifier]; [skpvc loadProductWithParameters: dict completionBlock: nil]; [[self _viewController] presentViewController: skpvc animated: YES completion: nil]; } else { static NSString* const iOS7AppStoreURLFormat = @"itms-apps://itunes.apple.com/app/id%@"; static NSString* const iOSAppStoreURLFormat = @"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=%@"; NSString* url = [[NSString alloc] initWithFormat: ([[UIDevice currentDevice].systemVersion floatValue] >= 7.0f) ? iOS7AppStoreURLFormat : iOSAppStoreURLFormat, cAppleID]; [[UIApplication sharedApplication] openURL: [NSURL URLWithString: url]]; }

已接受的答案未能加载“评审”选项卡。我发现下面的方法加载“审查”标签没有“详细信息”标签。

[[UIApplication sharedApplication] openURL:[NSURL URLWithString: @"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id={APP_ID}&pageNumber=0&sortOrdering=2&mt=8"]];

将{APP_ID}替换为你的app store app id。

使用这个URL对我来说是完美的解决方案。它将用户直接带到Write a Review部分。感谢@Joseph Duffy。必须努力

URL = itms-apps://itunes.apple.com/gb/app/idYOUR_APP_ID_HERE?action=write-review&mt=8 用你的AppId替换YOUR_APP_ID_HERE

对于一个示例代码，请尝试这样做:

Swift 3, Xcode 8.2.1:

 let openAppStoreForRating = "itms-apps://itunes.apple.com/gb/app/id1136613532?action=write-review&mt=8"
 if let url = URL(string: openAppStoreForRating), UIApplication.shared.canOpenURL(url) {
      UIApplication.shared.openURL(url)
 } else {
      showAlert(title: "Cannot open AppStore",message: "Please select our app from the AppStore and write a review for us. Thanks!!")
 }

这里showAlert是UIAlertController的自定义函数。

所有以前的链接不再直接到“评论”标签，

这个链接将直接指向“评论标签”: ​

https://itunes.apple.com/app/viewContentsUserReviews?id=AppID

or ​

itms-apps: / / itunes.apple.com/app/viewContentsUserReviews ? id = AppID