这是我的HTML表单:
<form name="myForm" ng-submit="">
<input ng-model='file' type="file"/>
<input type="submit" value='Submit'/>
</form>
我想从本地机器上传一个图像，并想读取上传文件的内容。所有这些我都想用AngularJS来做。
当我试图打印$scope的值时。文件是未定义的。
当前回答
这应该是对@jquery-guru的答案的更新/评论，但由于我没有足够的代表，它将在这里。它修复了现在由代码生成的错误。
https://jsfiddle.net/vzhrqotw/
变化主要是:
FileUploadCtrl.$inject = ['$scope']
function FileUploadCtrl(scope) {
To:
app.controller('FileUploadCtrl', function($scope)
{
如果需要，请随意搬到更合适的地方。
其他回答
我已经阅读了所有的线程，HTML5 API解决方案看起来最好。但它会改变我的二进制文件，以一种我没有调查过的方式破坏它们。最适合我的解决方案是:
HTML:
<input type="file" id="msds" ng-model="msds" name="msds"/>
<button ng-click="msds_update()">
Upload
</button>
JS:
msds_update = function() {
var f = document.getElementById('msds').files[0],
r = new FileReader();
r.onloadend = function(e) {
var data = e.target.result;
console.log(data);
var fd = new FormData();
fd.append('file', data);
fd.append('file_name', f.name);
$http.post('server_handler.php', fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(){
console.log('success');
})
.error(function(){
console.log('error');
});
};
r.readAsDataURL(f);
}
服务器端(PHP):
$file_content = $_POST['file'];
$file_content = substr($file_content,
strlen('data:text/plain;base64,'));
$file_content = base64_decode($file_content);
HTML
<html>
<head></head>
<body ng-app = "myApp">
<form ng-controller = "myCtrl">
<input type = "file" file-model="files" multiple/>
<button ng-click = "uploadFile()">upload me</button>
<li ng-repeat="file in files">{{file.name}}</li>
</form>
脚本
<script src =
"http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
<script>
angular.module('myApp', []).directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
element.bind('change', function(){
$parse(attrs.fileModel).assign(scope,element[0].files)
scope.$apply();
});
}
};
}]).controller('myCtrl', ['$scope', '$http', function($scope, $http){
$scope.uploadFile=function(){
var fd=new FormData();
console.log($scope.files);
angular.forEach($scope.files,function(file){
fd.append('file',file);
});
$http.post('http://localhost:1337/mediaobject/upload',fd,
{
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).success(function(d)
{
console.log(d);
})
}
}]);
</script>
上传文件
<input type="file" name="resume" onchange="angular.element(this).scope().uploadResume()" ng-model="fileupload" id="resume" />
$scope.uploadResume = function () {
var f = document.getElementById('resume').files[0];
$scope.selectedResumeName = f.name;
$scope.selectedResumeType = f.type;
r = new FileReader();
r.onloadend = function (e) {
$scope.data = e.target.result;
}
r.readAsDataURL(f);
};
下载文件:
<a href="{{applicant.resume}}" download> download resume</a>
var app = angular.module("myApp", []);
app.config(['$compileProvider', function ($compileProvider) {
$compileProvider.aHrefSanitizationWhitelist(/^\s*(https?|local|data|chrome-extension):/);
$compileProvider.imgSrcSanitizationWhitelist(/^\s*(https?|local|data|chrome-extension):/);
}]);
<input type=file>元素默认不使用ng-model指令。它需要一个自定义指令:
使用ng-model1的select-ng-files指令的工作演示
angular.module("app",[]); angular.module("app").directive("selectNgFiles", function() { return { require: "ngModel", link: function postLink(scope,elem,attrs,ngModel) { elem.on("change", function(e) { var files = elem[0].files; ngModel.$setViewValue(files); }) } } }); <script src="//unpkg.com/angular/angular.js"></script> <body ng-app="app"> <h1>AngularJS Input `type=file` Demo</h1> <input type="file" select-ng-files ng-model="fileList" multiple> <h2>Files</h2> <div ng-repeat="file in fileList"> {{file.name}} </div> </body>
美元http。从FileList中post
$scope.upload = function(url, fileList) {
var config = { headers: { 'Content-Type': undefined },
transformResponse: angular.identity
};
var promises = fileList.map(function(file) {
return $http.post(url, file, config);
});
return $q.all(promises);
};
当发送带有File对象的POST时，重要的是设置'Content-Type': undefined。然后XHR发送方法将检测File对象并自动设置内容类型。
该代码将帮助插入文件
<body ng-app = "myApp">
<form ng-controller="insert_Ctrl" method="post" action="" name="myForm" enctype="multipart/form-data" novalidate>
<div>
<p><input type="file" ng-model="myFile" class="form-control" onchange="angular.element(this).scope().uploadedFile(this)">
<span style="color:red" ng-show="(myForm.myFile.$error.required&&myForm.myFile.$touched)">Select Picture</span>
</p>
</div>
<div>
<input type="button" name="submit" ng-click="uploadFile()" class="btn-primary" ng-disabled="myForm.myFile.$invalid" value="insert">
</div>
</form>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>
<script src="insert.js"></script>
</body>
insert.js
var app = angular.module('myApp',[]);
app.service('uploadFile', ['$http','$window', function ($http,$window) {
this.uploadFiletoServer = function(file,uploadUrl){
var fd = new FormData();
fd.append('file', file);
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(data){
alert("insert successfull");
$window.location.href = ' ';//your window location
})
.error(function(){
alert("Error");
});
}
}]);
app.controller('insert_Ctrl', ['$scope', 'uploadFile', function($scope, uploadFile){
$scope.uploadFile = function() {
$scope.myFile = $scope.files[0];
var file = $scope.myFile;
var url = "save_data.php";
uploadFile.uploadFiletoServer(file,url);
};
$scope.uploadedFile = function(element) {
var reader = new FileReader();
reader.onload = function(event) {
$scope.$apply(function($scope) {
$scope.files = element.files;
$scope.src = event.target.result
});
}
reader.readAsDataURL(element.files[0]);
}
}]);
save_data.php
<?php
require "dbconnection.php";
$ext = pathinfo($_FILES['file']['name'],PATHINFO_EXTENSION);
$image = time().'.'.$ext;
move_uploaded_file($_FILES["file"]["tmp_name"],"upload/".$image);
$query="insert into test_table values ('null','$image')";
mysqli_query($con,$query);
?>
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