我想使用Java来获得文件的MD5校验和。我真的很惊讶,但我还没有找到任何东西,显示如何获得一个文件的MD5校验和。

这是怎么做到的?


当前回答

另一种实现:Java中的快速MD5实现

String hash = MD5.asHex(MD5.getHash(new File(filename)));

其他回答

public static String getMd5OfFile(String filePath)
{
    String returnVal = "";
    try 
    {
        InputStream   input   = new FileInputStream(filePath); 
        byte[]        buffer  = new byte[1024];
        MessageDigest md5Hash = MessageDigest.getInstance("MD5");
        int           numRead = 0;
        while (numRead != -1)
        {
            numRead = input.read(buffer);
            if (numRead > 0)
            {
                md5Hash.update(buffer, 0, numRead);
            }
        }
        input.close();

        byte [] md5Bytes = md5Hash.digest();
        for (int i=0; i < md5Bytes.length; i++)
        {
            returnVal += Integer.toString( ( md5Bytes[i] & 0xff ) + 0x100, 16).substring( 1 );
        }
    } 
    catch(Throwable t) {t.printStackTrace();}
    return returnVal.toUpperCase();
}

另一种实现:Java中的快速MD5实现

String hash = MD5.asHex(MD5.getHash(new File(filename)));

有一个输入流装饰器,java。security。DigestInputStream,这样您就可以像往常一样在使用输入流时计算摘要,而不必对数据进行额外的传递。

MessageDigest md = MessageDigest.getInstance("MD5");
try (InputStream is = Files.newInputStream(Paths.get("file.txt"));
     DigestInputStream dis = new DigestInputStream(is, md)) 
{
  /* Read decorated stream (dis) to EOF as normal... */
}
byte[] digest = md.digest();

非常快速和干净的java方法,不依赖于外部库:

(如果你想要,只需将MD5替换为SHA-1, SHA-256, SHA-384或SHA-512)

public String calcMD5() throws Exception{
        byte[] buffer = new byte[8192];
        MessageDigest md = MessageDigest.getInstance("MD5");

        DigestInputStream dis = new DigestInputStream(new FileInputStream(new File("Path to file")), md);
        try {
            while (dis.read(buffer) != -1);
        }finally{
            dis.close();
        }

        byte[] bytes = md.digest();

        // bytesToHex-method
        char[] hexChars = new char[bytes.length * 2];
        for ( int j = 0; j < bytes.length; j++ ) {
            int v = bytes[j] & 0xFF;
            hexChars[j * 2] = hexArray[v >>> 4];
            hexChars[j * 2 + 1] = hexArray[v & 0x0F];
        }

        return new String(hexChars);
}

从其他答案中提取想法,这里有一个简单的代码,没有第三方依赖关系(或DatatypeConverter,在最新的jdk中更长),将其生成为与md5sum工具输出兼容的十六进制字符串:

import java.io.IOException;
import java.math.BigInteger;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;
...

static String calculateMD5(String path) throws IOException
{
    try {
        MessageDigest md = MessageDigest.getInstance("MD5");
        md.update(Files.readAllBytes(Paths.get(path)));
        return String.format("%032x", new BigInteger(1, md.digest())); // hex, padded to 32 chars
    } catch (NoSuchAlgorithmException ex)
    {
        throw new RuntimeException(ex); // MD5 is always available so this should be impossible
    }
}