如果你知道数组有多少元素，一个简单的方法是这样做:

String appendedString = "" + array[0] + "" + array[1] + "" + array[2] + "" + array[3]; 

试试数组。toString重载方法。

否则，试试下面的通用实现:

public static void main(String... args) throws Exception {

    String[] array = {"ABC", "XYZ", "PQR"};

    System.out.println(new Test().join(array, ", "));
}

public <T> String join(T[] array, String cement) {
    StringBuilder builder = new StringBuilder();

    if(array == null || array.length == 0) {
        return null;
    }

    for (T t : array) {
        builder.append(t).append(cement);
    }

    builder.delete(builder.length() - cement.length(), builder.length());

    return builder.toString();
}

String array[]={"one","two"};
String s="";

for(int i=0;i<array.length;i++)
{
  s=s+array[i];
}

System.out.print(s);

public class ArrayToString
{   
    public static void main(String[] args)
    {
        String[] strArray = new String[]{"Java", "PHP", ".NET", "PERL", "C", "COBOL"};
        
        String newString = Arrays.toString(strArray);
        
        newString = newString.substring(1, newString.length()-1);

        System.out.println("New New String: " + newString);
    }
}

我喜欢使用谷歌的番石榴Joiner，例如:

Joiner.on(", ").skipNulls().join("Harry", null, "Ron", "Hermione");

将产生与以下相同的String:

new String("Harry, Ron, Hermione");

ETA: Java 8现在也有类似的支持:

String.join(", ", "Harry", "Ron", "Hermione");

不能看到跳过空值的支持，但这很容易解决。

如果你知道数组有多少元素，一个简单的方法是这样做:

String appendedString = "" + array[0] + "" + array[1] + "" + array[2] + "" + array[3];