还有更好的方法来用jUnit编写吗

String x = "foo bar";
Assert.assertTrue(x.contains("foo"));

当前回答

如果你添加Hamcrest和JUnit4,你可以这样做:

String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));

使用一些静态导入,它看起来好多了:

assertThat(x, containsString("foo"));

所需的静态导入是:

import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;

其他回答

与Hamcrest一起使用新的assertThat语法。

它可以从JUnit 4.4开始使用。

如果你添加Hamcrest和JUnit4,你可以这样做:

String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));

使用一些静态导入,它看起来好多了:

assertThat(x, containsString("foo"));

所需的静态导入是:

import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;

太晚了,但只是更新一下,我用下面的语法完成了它

import org.hamcrest.core.StringContains;
import org.junit.Assert;

Assert.assertThat("this contains test", StringContains.containsString("test"));

assertj变体

import org.assertj.core.api.Assertions;
Assertions.assertThat(actualStr).contains(subStr);

EDIT: assertj可能有更多断言(一个fork)

assertThat(x).contains("foo");