还有更好的方法来用jUnit编写吗
String x = "foo bar";
Assert.assertTrue(x.contains("foo"));
还有更好的方法来用jUnit编写吗
String x = "foo bar";
Assert.assertTrue(x.contains("foo"));
当前回答
如果你添加Hamcrest和JUnit4,你可以这样做:
String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));
使用一些静态导入,它看起来好多了:
assertThat(x, containsString("foo"));
所需的静态导入是:
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;
其他回答
与Hamcrest一起使用新的assertThat语法。
它可以从JUnit 4.4开始使用。
如果你添加Hamcrest和JUnit4,你可以这样做:
String x = "foo bar";
Assert.assertThat(x, CoreMatchers.containsString("foo"));
使用一些静态导入,它看起来好多了:
assertThat(x, containsString("foo"));
所需的静态导入是:
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.CoreMatchers.containsString;
太晚了,但只是更新一下,我用下面的语法完成了它
import org.hamcrest.core.StringContains;
import org.junit.Assert;
Assert.assertThat("this contains test", StringContains.containsString("test"));
assertj变体
import org.assertj.core.api.Assertions;
Assertions.assertThat(actualStr).contains(subStr);
EDIT: assertj可能有更多断言(一个fork)
assertThat(x).contains("foo");