代码:

string someString1 = "\tHello\r\n\tWorld!\r\n";
string someString2 = @"\tHello\r\n\tWorld!\r\n";

Console.WriteLine(someString1);
Console.WriteLine(someString2);

输出:

    Hello
    World!

\tHello\r\n\tWorld!\r\n

有趣的问题。

如果你找不到更好的方法，你可以随时替换。 如果你选择它，你可以使用这个c#转义序列列表:

\' - single quote, needed for character literals \" - double quote, needed for string literals \ - backslash \0 - Unicode character 0 \a - Alert (character 7) \b - Backspace (character 8) \f - Form feed (character 12) \n - New line (character 10) \r - Carriage return (character 13) \t - Horizontal tab (character 9) \v - Vertical quote (character 11) \uxxxx - Unicode escape sequence for character with hex value xxxx \xn[n][n][n] - Unicode escape sequence for character with hex value nnnn (variable length version of \uxxxx) \Uxxxxxxxx - Unicode escape sequence for character with hex value xxxxxxxx (for generating surrogates)

这个列表可以在c#常见问题中找到 有哪些字符转义序列可用?

Roslyn在NuGet上的Microsoft.CodeAnalysis.CSharp包中有一个方法:

private static string ToLiteral(string valueTextForCompiler)
{
    return Microsoft.CodeAnalysis.CSharp.SymbolDisplay.FormatLiteral(valueTextForCompiler, false);
}

显然，这在最初的问题时并不存在，但它可能会帮助那些从谷歌搜索到这里的人。

public static class StringEscape
{
  static char[] toEscape = "\0\x1\x2\x3\x4\x5\x6\a\b\t\n\v\f\r\xe\xf\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f\"\\".ToCharArray();
  static string[] literals = @"\0,\x0001,\x0002,\x0003,\x0004,\x0005,\x0006,\a,\b,\t,\n,\v,\f,\r,\x000e,\x000f,\x0010,\x0011,\x0012,\x0013,\x0014,\x0015,\x0016,\x0017,\x0018,\x0019,\x001a,\x001b,\x001c,\x001d,\x001e,\x001f".Split(new char[] { ',' });

  public static string Escape(this string input)
  {
    int i = input.IndexOfAny(toEscape);
    if (i < 0) return input;

    var sb = new System.Text.StringBuilder(input.Length + 5);
    int j = 0;
    do
    {
      sb.Append(input, j, i - j);
      var c = input[i];
      if (c < 0x20) sb.Append(literals[c]); else sb.Append(@"\").Append(c);
    } while ((i = input.IndexOfAny(toEscape, j = ++i)) > 0);

    return sb.Append(input, j, input.Length - j).ToString();
  }
}

Hallgrim的回答很好，但是“+”，换行和缩进的添加破坏了我的功能。一个简单的解决方法是:

private static string ToLiteral(string input)
{
    using (var writer = new StringWriter())
    {
        using (var provider = CodeDomProvider.CreateProvider("CSharp"))
        {
            provider.GenerateCodeFromExpression(new CodePrimitiveExpression(input), writer, new CodeGeneratorOptions {IndentString = "\t"});
            var literal = writer.ToString();
            literal = literal.Replace(string.Format("\" +{0}\t\"", Environment.NewLine), "");
            return literal;
        }
    }
}

代码:

string someString1 = "\tHello\r\n\tWorld!\r\n";
string someString2 = @"\tHello\r\n\tWorld!\r\n";

Console.WriteLine(someString1);
Console.WriteLine(someString2);

输出:

    Hello
    World!

\tHello\r\n\tWorld!\r\n