我有一个字符串数组,我需要在JavaScript中排序,但以不区分大小写的方式。如何做到这一点?
当前回答
其他答案假设数组包含字符串。我的方法更好,因为即使数组包含null、undefined或其他非字符串,它也能工作。
var notdefined;
var myarray = ['a', 'c', null, notdefined, 'nulk', 'BYE', 'nulm'];
myarray.sort(ignoreCase);
alert(JSON.stringify(myarray)); // show the result
function ignoreCase(a,b) {
return (''+a).toUpperCase() < (''+b).toUpperCase() ? -1 : 1;
}
null将在'nulk'和'nulm'之间排序。但未定义的总是排在最后。
其他回答
在(几乎:)一行代码中
["Foo", "bar"].sort(function (a, b) {
return a.toLowerCase().localeCompare(b.toLowerCase());
});
结果是
[ 'bar', 'Foo' ]
而
["Foo", "bar"].sort();
结果
[ 'Foo', 'bar' ]
现在是时候重新审视这个老问题了。
您不应该使用依赖toLowerCase的解决方案。它们效率很低,而且在某些语言(例如土耳其语)中根本不起作用。喜欢这个:
['Foo', 'bar'].sort((a, b) => a.localeCompare(b, undefined, {sensitivity: 'base'}))
查看浏览器兼容性文档,了解灵敏度选项的所有信息。
如果你在努力理解以下内容,这可能会有所帮助:
var array = ["sort", "Me", "alphabetically", "But", "Ignore", "case"];
console.log('Unordered array ---', array, '------------');
array.sort(function(a,b) {
a = a.toLowerCase();
b = b.toLowerCase();
console.log("Compare '" + a + "' and '" + b + "'");
if( a == b) {
console.log('Comparison result, 0 --- leave as is ');
return 0;
}
if( a > b) {
console.log('Comparison result, 1 --- move '+b+' to before '+a+' ');
return 1;
}
console.log('Comparison result, -1 --- move '+a+' to before '+b+' ');
return -1;
});
console.log('Ordered array ---', array, '------------');
// return logic
/***
If compareFunction(a, b) is less than 0, sort a to a lower index than b, i.e. a comes first.
If compareFunction(a, b) returns 0, leave a and b unchanged with respect to each other, but sorted with respect to all different elements. Note: the ECMAscript standard does not guarantee this behaviour, and thus not all browsers (e.g. Mozilla versions dating back to at least 2003) respect this.
If compareFunction(a, b) is greater than 0, sort b to a lower index than a.
***/
http://jsfiddle.net/ianjamieson/wmxn2ram/1/
ES6版本:
["Foo", "bar"].sort(Intl.Collator().compare)
来源:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Collator/compare
在/ /i中包装字符串。这是使用正则表达式忽略大小写的一种简单方法