我有一个Person对象列表。我想转换为Dictionary，其中键是第一个和最后一个名字(连接)，值是Person对象。
问题是我有一些重复的人，所以这爆炸如果我使用以下代码:
private Dictionary<string, Person> _people = new Dictionary<string, Person>();
_people = personList.ToDictionary(
e => e.FirstandLastName,
StringComparer.OrdinalIgnoreCase);
我知道这听起来很奇怪，但我现在真的不关心重复的名字。如果有多个名字，我只想取一个。有没有什么方法可以让上面的代码只取其中一个名字而不会重复?
当前回答
LINQ的解决方案:
// Use the first value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.First(), StringComparer.OrdinalIgnoreCase);
// Use the last value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.Last(), StringComparer.OrdinalIgnoreCase);
如果你更喜欢非linq解决方案，那么你可以这样做:
// Use the first value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
if (!_people.ContainsKey(p.FirstandLastName))
_people[p.FirstandLastName] = p;
}
// Use the last value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
_people[p.FirstandLastName] = p;
}
其他回答
LINQ的解决方案:
// Use the first value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.First(), StringComparer.OrdinalIgnoreCase);
// Use the last value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.Last(), StringComparer.OrdinalIgnoreCase);
如果你更喜欢非linq解决方案，那么你可以这样做:
// Use the first value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
if (!_people.ContainsKey(p.FirstandLastName))
_people[p.FirstandLastName] = p;
}
// Use the last value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
_people[p.FirstandLastName] = p;
}
从Carra的解开始，你也可以把它写成:
foreach(var person in personList.Where(el => !myDictionary.ContainsKey(el.FirstAndLastName)))
{
myDictionary.Add(person.FirstAndLastName, person);
}
如果我们想要返回字典中的所有Person(而不是只有一个Person)，我们可以:
var _people = personList
.GroupBy(p => p.FirstandLastName)
.ToDictionary(g => g.Key, g => g.Select(x=>x));
大多数其他答案的问题是，他们使用Distinct, GroupBy或ToLookup，这在底层创建了一个额外的字典。同样ToUpper创建额外的字符串。 这就是我所做的，除了一处更改外，几乎完全复制了微软的代码:
public static Dictionary<TKey, TSource> ToDictionaryIgnoreDup<TSource, TKey>
(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector, IEqualityComparer<TKey> comparer = null) =>
source.ToDictionaryIgnoreDup(keySelector, i => i, comparer);
public static Dictionary<TKey, TElement> ToDictionaryIgnoreDup<TSource, TKey, TElement>
(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector, Func<TSource, TElement> elementSelector, IEqualityComparer<TKey> comparer = null)
{
if (keySelector == null)
throw new ArgumentNullException(nameof(keySelector));
if (elementSelector == null)
throw new ArgumentNullException(nameof(elementSelector));
var d = new Dictionary<TKey, TElement>(comparer ?? EqualityComparer<TKey>.Default);
foreach (var element in source)
d[keySelector(element)] = elementSelector(element);
return d;
}
因为索引器上的set会导致它添加键，所以它不会抛出，也只会进行一次键查找。你也可以给它一个IEqualityComparer，例如StringComparer。OrdinalIgnoreCase
DataTable DT = new DataTable();
DT.Columns.Add("first", typeof(string));
DT.Columns.Add("second", typeof(string));
DT.Rows.Add("ss", "test1");
DT.Rows.Add("sss", "test2");
DT.Rows.Add("sys", "test3");
DT.Rows.Add("ss", "test4");
DT.Rows.Add("ss", "test5");
DT.Rows.Add("sts", "test6");
var dr = DT.AsEnumerable().GroupBy(S => S.Field<string>("first")).Select(S => S.First()).
Select(S => new KeyValuePair<string, string>(S.Field<string>("first"), S.Field<string>("second"))).
ToDictionary(S => S.Key, T => T.Value);
foreach (var item in dr)
{
Console.WriteLine(item.Key + "-" + item.Value);
}
