如何从Django模板中获取当前站点的域名?我试着在标签和过滤器中寻找,但没有什么。


当前回答

下面这些可以获得完整的url和部分url:

def myview(request):
    request.build_absolute_uri()
    # http://localhost:8000/admin/store/product/

    request.build_absolute_uri('/')
    # http://localhost:8000/

    request.build_absolute_uri('/')[:-1]
    # http://localhost:8000

    request.scheme
    # http

    request.META['HTTP_HOST']
    # localhost:8000

    request.path    
    # /admin/store/product/

其他回答

我知道这个问题很老了,但我是在寻找一种python方法来获取当前域时偶然发现的。

def myview(request):
    domain = request.build_absolute_uri('/')[:-1]
    # that will build the complete domain: http://foobar.com

您可以在模板中使用{{protocol}}://{{domain}}来获取您的域名。

我发现了{{请求。Get_host}}方法。

我认为我们想要的是现有url标签的替代品,所以我写了一个新标签:

from django.template import Library
from django.urls     import reverse

@register.simple_tag(takes_context = True)
def fullURL(context, name, *args, **kwargs):
    request = context['request']
    return f'{request.scheme}://{request.get_host()}{reverse(name, args = args, kwargs = kwargs)}'

然后在你的模板中你可以这样…

{% extends "myapp/email/email_base.html" %}

{% load mytags %} {# Replace mytags with whatever the name of your custom tags calss is. #}

{% block content %}
<p>You can use <a href="{% fullURL 'signup' %}">this link</a> to get started with your account. We look forward to seeing you soon!</p>
{% endblock content %}

然后,当你生成这个时,你只需要记住将请求传递到上下文,就像这样……

from django.template.loader import render_to_string

def sendEmail(subject, to, template, **context):
    html = render_to_string(f'myapp/email/{template}.html', context | {'subject': subject})
    # ... and so on with the rest of my function for sending email...

{{请求。get_host}}在和ALLOWED_HOSTS设置(在Django 1.4.4中添加)一起使用时,可以防止HTTP主机头攻击。

注意{{request.META。HTTP_HOST}}没有相同的保护。查看文档:

ALLOWED_HOSTS A list of strings representing the host/domain names that this Django site can serve. This is a security measure to prevent HTTP Host header attacks, which are possible even under many seemingly-safe web server configurations. ... If the Host header (or X-Forwarded-Host if USE_X_FORWARDED_HOST is enabled) does not match any value in this list, the django.http.HttpRequest.get_host() method will raise SuspiciousOperation. ... This validation only applies via get_host(); if your code accesses the Host header directly from request.META you are bypassing this security protection.


至于在模板中使用请求,在Django 1.8中,模板渲染函数调用已经改变了,所以你不再需要直接处理RequestContext。

下面是如何渲染视图的模板,使用快捷函数render():

from django.shortcuts import render

def my_view(request):
    ...
    return render(request, 'my_template.html', context)

下面是如何呈现一个电子邮件模板,IMO是更常见的情况下,你想要的主机值:

from django.template.loader import render_to_string

def my_view(request):
    ...
    email_body = render_to_string(
        'my_template.txt', context, request=request)

下面是一个在电子邮件模板中添加完整URL的示例;请求。Scheme应该获得HTTP或HTTPS,这取决于您使用的是什么:

Thanks for registering! Here's your activation link:
{{ request.scheme }}://{{ request.get_host }}{% url 'registration_activate' activation_key %}