所以我试图使用JavaScript滚动调用一个函数。但是我想知道我是否可以不使用jQuery检测滚动的方向。如果没有，有什么变通办法吗?
我想只放一个“顶部”按钮，但如果可以的话，我想避免这个按钮。
我现在刚刚尝试使用这段代码，但它不起作用:
if document.body.scrollTop <= 0 {
alert ("scrolling down")
} else {
alert ("scrolling up")
}
当前回答
可以通过存储之前的scrollTop值并将当前scrollTop值与其进行比较来检测它。
JavaScript:
var lastScrollTop = 0;
// element should be replaced with the actual target element on which you have applied scroll, use window in case of no target element.
element.addEventListener("scroll", function(){ // or window.addEventListener("scroll"....
var st = window.pageYOffset || document.documentElement.scrollTop; // Credits: "https://github.com/qeremy/so/blob/master/so.dom.js#L426"
if (st > lastScrollTop) {
// downscroll code
} else if (st < lastScrollTop) {
// upscroll code
} // else was horizontal scroll
lastScrollTop = st <= 0 ? 0 : st; // For Mobile or negative scrolling
}, false);
其他回答
捕捉所有滚动事件(触摸和滚轮)的简单方法
window.onscroll = function(e) {
// print "false" if direction is down and "true" if up
console.log(this.oldScroll > this.scrollY);
this.oldScroll = this.scrollY;
}
修改Prateek的答案，如果lastScrollTop没有变化，那么它将是一个水平滚动(在x方向溢出，可以使用鼠标使用水平滚动条或使用滚动轮+ shift来使用。
const containerElm = document.getElementById("container");
let lastScrollTop = containerElm.scrollTop;
containerElm.addEventListener("scroll", (evt) => {
const st = containerElm.scrollTop;
if (st > lastScrollTop) {
console.log("down scroll");
} else if (st < lastScrollTop) {
console.log("up scroll");
} else {
console.log("horizontal scroll");
}
lastScrollTop = Math.max(st, 0); // For mobile or negative scrolling
});
你可以试试这样做。
function scrollDetect(){ var lastScroll = 0; window.onscroll = function() { let currentScroll = document.documentElement.scrollTop || document.body.scrollTop; // Get Current Scroll Value if (currentScroll > 0 && lastScroll <= currentScroll){ lastScroll = currentScroll; document.getElementById("scrollLoc").innerHTML = "Scrolling DOWN"; }else{ lastScroll = currentScroll; document.getElementById("scrollLoc").innerHTML = "Scrolling UP"; } }; } scrollDetect(); html,body{ height:100%; width:100%; margin:0; padding:0; } .cont{ height:100%; width:100%; } .item{ margin:0; padding:0; height:100%; width:100%; background: #ffad33; } .red{ background: red; } p{ position:fixed; font-size:25px; top:5%; left:5%; } <div class="cont"> <div class="item"></div> <div class="item red"></div> <p id="scrollLoc">0</p> </div>
如果有人想用React钩子实现它
const [scrollStatus, setScrollStatus] = useState({
scrollDirection: null,
scrollPos: 0,
});
useEffect(() => {
window.addEventListener("scroll", handleScrollDocument);
return () => window.removeEventListener("scroll", handleScrollDocument);
}, []);
function handleScrollDocument() {
setScrollStatus((prev) => { // to get 'previous' value of state
return {
scrollDirection:
document.body.getBoundingClientRect().top > prev.scrollPos
? "up"
: "down",
scrollPos: document.body.getBoundingClientRect().top,
};
});
}
console.log(scrollStatus.scrollDirection)
这是对prateek的回答的补充。在IE的代码中似乎有一个小故障，所以我决定修改它一点也不花哨(只是另一个条件)
$('document').ready(function() {
var lastScrollTop = 0;
$(window).scroll(function(event){
var st = $(this).scrollTop();
if (st > lastScrollTop){
console.log("down")
}
else if(st == lastScrollTop)
{
//do nothing
//In IE this is an important condition because there seems to be some instances where the last scrollTop is equal to the new one
}
else {
console.log("up")
}
lastScrollTop = st;
});});
