我使用JAVA 1.6和Jackson 1.9.9,我有一个enum

public enum Event {
    FORGOT_PASSWORD("forgot password");

    private final String value;

    private Event(final String description) {
        this.value = description;
    }

    @JsonValue
    final String value() {
        return this.value;
    }
}

我已经添加了一个@JsonValue,这似乎做的工作,它序列化对象:

{"event":"forgot password"}

但当我尝试反序列化时,我得到

Caused by: org.codehaus.jackson.map.JsonMappingException: Can not construct instance of com.globalrelay.gas.appsjson.authportal.Event from String value 'forgot password': value not one of declared Enum instance names

我错过了什么?


当前回答

我发现最简单的方法是使用@JsonFormat.Shape。枚举的OBJECT注释。

@JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum MyEnum{
    ....
}

其他回答

我一直在寻找枚举序列化的解决方案,我终于做出了一个解决方案。

https://github.com/sirgilligan/EnumerationSerialization

https://digerati-illuminatus.blogspot.com/2022/10/java-enum-generic-serializer-and.html

它使用了一个新的注释和两个新类EnumerationSerializer和EnumerationDeserializer。您可以子类化EnumerationDeserializer,并创建一个设置枚举class的类(典型方法),或者您可以注释枚举,并且不必拥有EnumerationDeserializer的子类。

@JsonSerialize(using = EnumerationSerializer.class)
@JsonDeserialize(using = EnumerationDeserializer.class)
@EnumJson(serializeProjection = Projection.NAME, deserializationClass = RGB.class)
enum RGB {
    RED,
    GREEN,
    BLUE
}

注意ContextualDeserializer的实现如何从注释中提取类。

https://github.com/sirgilligan/EnumerationSerialization/blob/main/src/main/java/org/example/EnumerationDeserializer.java

这里有很多很好的代码,可以提供一些见解。

对于你的具体问题,你可以这样做:

@JsonSerialize(using = EnumerationSerializer.class)
@JsonDeserialize(using = EnumerationDeserializer.class)
@EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
    FORGOT_PASSWORD("forgot password");

    //This annotation is optional because the code looks for value or alias.
    @EnumJson(serializeProjection = Projection.VALUE)
    private final String value;

    private Event(final String description) {
        this.value = description;
    }

}

或者你可以这样做:

@JsonSerialize(using = EnumerationSerializer.class)
@JsonDeserialize(using = EnumerationDeserializer.class)
@EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
    FORGOT_PASSWORD("forgot password");

    private final String value;

    private Event(final String description) {
        this.value = description;
    }

}

这就是你要做的。

然后,如果您有一个“有”事件的类,您可以注释每个事件以您想要的方式序列化。

class EventHolder {
    @EnumJson(serializeProjection = Projection.NAME)
    Event someEvent;

    @EnumJson(serializeProjection = Projection.ORDINAL)
    Event someOtherEvent;

    @EnumJson(serializeProjection = Projection.VALUE)
    Event yetAnotherEvent;
}

下面是另一个使用字符串值而不是映射的例子。

public enum Operator {
    EQUAL(new String[]{"=","==","==="}),
    NOT_EQUAL(new String[]{"!=","<>"}),
    LESS_THAN(new String[]{"<"}),
    LESS_THAN_EQUAL(new String[]{"<="}),
    GREATER_THAN(new String[]{">"}),
    GREATER_THAN_EQUAL(new String[]{">="}),
    EXISTS(new String[]{"not null", "exists"}),
    NOT_EXISTS(new String[]{"is null", "not exists"}),
    MATCH(new String[]{"match"});

    private String[] value;

    Operator(String[] value) {
        this.value = value;
    }

    @JsonValue
    public String toStringOperator(){
        return value[0];
    }

    @JsonCreator
    public static Operator fromStringOperator(String stringOperator) {
        if(stringOperator != null) {
            for(Operator operator : Operator.values()) {
                for(String operatorString : operator.value) {
                    if (stringOperator.equalsIgnoreCase(operatorString)) {
                        return operator;
                    }
                }
            }
        }
        return null;
    }
}

试试这个。

public enum Event {

    FORGOT_PASSWORD("forgot password");

    private final String value;

    private Event(final String description) {
        this.value = description;
    }

    private Event() {
        this.value = this.name();
    }

    @JsonValue
    final String value() {
        return this.value;
    }
}

我是这样做的:

// Your JSON
{"event":"forgot password"}

// Your class to map 
public class LoggingDto {
    @JsonProperty(value = "event")
    private FooEnum logType;
}

//Your enum
public enum FooEnum {

    DATA_LOG ("Dummy 1"),
    DATA2_LOG ("Dummy 2"),
    DATA3_LOG ("forgot password"),
    DATA4_LOG ("Dummy 4"),
    DATA5_LOG ("Dummy 5"),
    UNKNOWN ("");

    private String fullName;

    FooEnum(String fullName) {
        this.fullName = fullName;
    }

    public String getFullName() {
        return fullName;
    }

    @JsonCreator
    public static FooEnum getLogTypeFromFullName(String fullName) {
        for (FooEnum logType : FooEnum.values()) {
            if (logType.fullName.equals(fullName)) {
                return logType;
            }
        }
        return UNKNOWN;
    }


}

因此,类LoggingDto的属性“logType”的值将是DATA3_LOG

我发现最简单的方法是使用@JsonFormat.Shape。枚举的OBJECT注释。

@JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum MyEnum{
    ....
}