有没有更好的方法来使用glob。Glob在python中获取多个文件类型的列表,如.txt, .mdown和.markdown?现在我有这样的东西:

projectFiles1 = glob.glob( os.path.join(projectDir, '*.txt') )
projectFiles2 = glob.glob( os.path.join(projectDir, '*.mdown') )
projectFiles3 = glob.glob( os.path.join(projectDir, '*.markdown') )

当前回答

链接结果:

import itertools as it, glob

def multiple_file_types(*patterns):
    return it.chain.from_iterable(glob.iglob(pattern) for pattern in patterns)

然后:

for filename in multiple_file_types("*.txt", "*.sql", "*.log"):
    # do stuff

其他回答

还有另一个解决方案(使用glob使用多个匹配模式获取路径,并使用reduce和add将所有路径组合到一个列表中):

import functools, glob, operator
paths = functools.reduce(operator.add, [glob.glob(pattern) for pattern in [
    "path1/*.ext1",
    "path2/*.ext2"]])

使用扩展列表并遍历

from os.path import join
from glob import glob

files = []
extensions = ['*.gif', '*.png', '*.jpg']
for ext in extensions:
   files.extend(glob(join("path/to/dir", ext)))

print(files)

最简单的方法是使用itertools.chain

from pathlib import Path
import itertools

cwd = Path.cwd()

for file in itertools.chain(
    cwd.rglob("*.txt"),
    cwd.rglob("*.md"),
):
    print(file.name)

从前面的答案

glob('*.jpg') + glob('*.png')

这是一个较短的问题,

from glob import glob
extensions = ['jpg', 'png'] # to find these filename extensions

# Method 1: loop one by one and extend to the output list
output = []
[output.extend(glob(f'*.{name}')) for name in extensions]
print(output)

# Method 2: even shorter
# loop filename extension to glob() it and flatten it to a list
output = [p for p2 in [glob(f'*.{name}') for name in extensions] for p in p2]
print(output)
from glob import glob

files = glob('*.gif')
files.extend(glob('*.png'))
files.extend(glob('*.jpg'))

print(files)

如果你需要指定一个路径,循环匹配模式,并保持连接在循环中简单:

from os.path import join
from glob import glob

files = []
for ext in ('*.gif', '*.png', '*.jpg'):
   files.extend(glob(join("path/to/dir", ext)))

print(files)