有人能为我提供一个导入整个模块目录的好方法吗? 我有一个这样的结构:
/Foo
bar.py
spam.py
eggs.py
我尝试通过添加__init__.py并从Foo import *将其转换为一个包,但它没有按我希望的方式工作。
有人能为我提供一个导入整个模块目录的好方法吗? 我有一个这样的结构:
/Foo
bar.py
spam.py
eggs.py
我尝试通过添加__init__.py并从Foo import *将其转换为一个包,但它没有按我希望的方式工作。
当前回答
我自己也厌倦了这个问题,所以我写了一个名为automodinit的包来解决它。你可以从http://pypi.python.org/pypi/automodinit/上得到它。
用法是这样的:
将automodinit包包含到setup.py依赖项中。 像这样替换所有__init__.py文件:
__all__ = ["I will get rewritten"] # Don't modify the line above, or this line! import automodinit automodinit.automodinit(__name__, __file__, globals()) del automodinit # Anything else you want can go after here, it won't get modified.
就是这样!从现在开始导入一个模块将设置__all__为 模块中的.py[co]文件列表,也将导入每个文件 就好像你输入了:
for x in __all__: import x
因此,“from M import *”的效果与“import M”完全匹配。
automodinit从ZIP档案内部运行,因此是ZIP安全的。
尼尔
其他回答
这里有一个解决方案,您不必写文件名。只需将此代码片段添加到__init__.py中
from inspect import isclass
from pkgutil import iter_modules
from pathlib import Path
from importlib import import_module
# iterate through the modules in the current package
package_dir = Path(__file__).resolve().parent
for (_, module_name, _) in iter_modules([package_dir]):
# import the module and iterate through its attributes
module = import_module(f"{__name__}.{module_name}")
for attribute_name in dir(module):
attribute = getattr(module, attribute_name)
if isclass(attribute):
# Add the class to this package's variables
globals()[attribute_name] = attribute
源
将__all__变量添加到__init__.py,包含:
__all__ = ["bar", "spam", "eggs"]
参见http://docs.python.org/tutorial/modules.html
注意你的__init__.py定义了__all__。模块-包文档说
The __init__.py files are required to make Python treat the directories as containing packages; this is done to prevent directories with a common name, such as string, from unintentionally hiding valid modules that occur later on the module search path. In the simplest case, __init__.py can just be an empty file, but it can also execute initialization code for the package or set the __all__ variable, described later. ... The only solution is for the package author to provide an explicit index of the package. The import statement uses the following convention: if a package’s __init__.py code defines a list named __all__, it is taken to be the list of module names that should be imported when from package import * is encountered. It is up to the package author to keep this list up-to-date when a new version of the package is released. Package authors may also decide not to support it, if they don’t see a use for importing * from their package. For example, the file sounds/effects/__init__.py could contain the following code: __all__ = ["echo", "surround", "reverse"] This would mean that from sound.effects import * would import the three named submodules of the sound package.
我有一个嵌套的目录结构,即在包含python模块的主目录中有多个目录。
我在__init__.py文件中添加了以下脚本以导入所有模块
import glob, re, os
module_parent_directory = "path/to/the/directory/containing/__init__.py/file"
owd = os.getcwd()
if not owd.endswith(module_parent_directory): os.chdir(module_parent_directory)
module_paths = glob.glob("**/*.py", recursive = True)
for module_path in module_paths:
if not re.match( ".*__init__.py$", module_path):
import_path = module_path[:-3]
import_path = import_path.replace("/", ".")
exec(f"from .{import_path} import *")
os.chdir(owd)
也许这不是实现这一目标的最佳方式,但除此之外我没有别的办法。
列出当前文件夹中的所有python (.py)文件,并将它们作为__init__.py中的__all__变量
from os.path import dirname, basename, isfile, join
import glob
modules = glob.glob(join(dirname(__file__), "*.py"))
__all__ = [ basename(f)[:-3] for f in modules if isfile(f) and not f.endswith('__init__.py')]