我在iBooks上读了苹果的编程语言Swift,但不知道如何在Swift中发出HTTP请求(类似cURL)。我需要导入Obj-C类还是只需要导入默认库?或者不能基于原生Swift代码进行HTTP请求?
当前回答
我已经完成了HTTP请求两种方法GET和POST与JSON解析的方式:
在viewDidLoad ():
override func viewDidLoad() {
super.viewDidLoad()
makeGetRequest()
makePostRequest()
}
func makePostRequest(){
let urlPath: String = "http://www.swiftdeveloperblog.com/http-post-example-script/"
var url: NSURL = NSURL(string: urlPath)!
var request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
var stringPost="firstName=James&lastName=Bond" // Key and Value
let data = stringPost.dataUsingEncoding(NSUTF8StringEncoding)
request.timeoutInterval = 60
request.HTTPBody=data
request.HTTPShouldHandleCookies=false
let queue:NSOperationQueue = NSOperationQueue()
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(), completionHandler:{ (response:NSURLResponse!, data: NSData!, error: NSError!) -> Void in
var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil
let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary
if (jsonResult != nil) {
// Success
println(jsonResult)
let message = jsonResult["Message"] as! NSString
println(message)
}else {
// Failed
println("Failed")
}
})
}
func makeGetRequest(){
var url : String = "http://api.androidhive.info/contacts/"
var request : NSMutableURLRequest = NSMutableURLRequest()
request.URL = NSURL(string: url)
request.HTTPMethod = "GET"
request.timeoutInterval = 60
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(), completionHandler:{ (response:NSURLResponse!, data: NSData!, error: NSError!) -> Void in
var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil
let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary
if (jsonResult != nil) {
// Success
println(jsonResult)
let dataArray = jsonResult["contacts"] as! NSArray;
for item in dataArray { // loop through data items
let obj = item as! NSDictionary
for (key, value) in obj {
println("Key: \(key) - Value: \(value)")
let phone = obj["phone"] as! NSDictionary;
let mobile = phone["mobile"] as! NSString
println(mobile)
let home = phone["home"] as! NSString
println(home)
let office = phone["office"] as! NSString
println(office)
}
}
} else {
// Failed
println("Failed")
}
})
}
Done
其他回答
var post:NSString = "api=myposts&userid=\(uid)&page_no=0&limit_no=10"
NSLog("PostData: %@",post);
var url1:NSURL = NSURL(string: url)!
var postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!
var postLength:NSString = String( postData.length )
var request:NSMutableURLRequest = NSMutableURLRequest(URL: url1)
request.HTTPMethod = "POST"
request.HTTPBody = postData
request.setValue(postLength, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
var reponseError: NSError?
var response: NSURLResponse?
var urlData: NSData? = NSURLConnection.sendSynchronousRequest(request, returningResponse:&response, error:&reponseError)
if ( urlData != nil ) {
let res = response as NSHTTPURLResponse!;
NSLog("Response code: %ld", res.statusCode);
if (res.statusCode >= 200 && res.statusCode < 300)
{
var responseData:NSString = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!
NSLog("Response ==> %@", responseData);
var error: NSError?
let jsonData:NSDictionary = NSJSONSerialization.JSONObjectWithData(urlData!, options:NSJSONReadingOptions.MutableContainers , error: &error) as NSDictionary
let success:NSInteger = jsonData.valueForKey("error") as NSInteger
//[jsonData[@"success"] integerValue];
NSLog("Success: %ld", success);
if(success == 0)
{
NSLog("Login SUCCESS");
self.dataArr = jsonData.valueForKey("data") as NSMutableArray
self.table.reloadData()
} else {
NSLog("Login failed1");
ZAActivityBar.showErrorWithStatus("error", forAction: "Action2")
}
} else {
NSLog("Login failed2");
ZAActivityBar.showErrorWithStatus("error", forAction: "Action2")
}
} else {
NSLog("Login failed3");
ZAActivityBar.showErrorWithStatus("error", forAction: "Action2")
}
它一定会对你有帮助
我调用json登录按钮点击
@IBAction func loginClicked(sender : AnyObject) {
var request = NSMutableURLRequest(URL: NSURL(string: kLoginURL)) // Here, kLogin contains the Login API.
var session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"
var err: NSError?
request.HTTPBody = NSJSONSerialization.dataWithJSONObject(self.criteriaDic(), options: nil, error: &err) // This Line fills the web service with required parameters.
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
var strData = NSString(data: data, encoding: NSUTF8StringEncoding)
var err1: NSError?
var json2 = NSJSONSerialization.JSONObjectWithData(strData.dataUsingEncoding(NSUTF8StringEncoding), options: .MutableLeaves, error:&err1 ) as NSDictionary
println("json2 :\(json2)")
if(err) {
println(err!.localizedDescription)
}
else {
var success = json2["success"] as? Int
println("Success: \(success)")
}
})
task.resume()
}
在这里,我为参数创建了一个单独的字典。
var params = ["format":"json", "MobileType":"IOS","MIN":"f8d16d98ad12acdbbe1de647414495ec","UserName":emailTxtField.text,"PWD":passwordTxtField.text,"SigninVia":"SH"]as NSDictionary
return params
}
// You can add your own sets of parameter here.
答:吻
URLSession.shared.dataTask(with: URL(string: "https://google.com")!) {(data, response, error) in
print(String(data: data!, encoding: .utf8))
}.resume()
你可以使用URL URLRequest URLSession或者NSURLConnection就像你在Objective-C中通常做的那样。注意,对于iOS 7.0及更高版本,URLSession是首选。
使用URLSession
初始化URL对象和URLSession中的URLSessionDataTask。然后使用resume()运行任务。
let url = URL(string: "http://www.stackoverflow.com")!
let task = URLSession.shared.dataTask(with: url) {(data, response, error) in
guard let data = data else { return }
print(String(data: data, encoding: .utf8)!)
}
task.resume()
使用NSURLConnection
首先,初始化URL和URLRequest:
let url = URL(string: "http://www.stackoverflow.com")!
var request = URLRequest(url: url)
request.httpMethod = "POST"
然后,你可以异步加载请求:
NSURLConnection.sendAsynchronousRequest(request, queue: OperationQueue.main) {(response, data, error) in
guard let data = data else { return }
print(String(data: data, encoding: .utf8)!)
}
或者你可以初始化一个NSURLConnection:
let connection = NSURLConnection(request: request, delegate:nil, startImmediately: true)
只是要确保将委托设置为nil以外的东西,并使用委托方法处理接收到的响应和数据。
要了解更多细节,请查看NSURLConnectionDataDelegate协议的文档
在Xcode操场上测试
如果你想在Xcode游乐场上尝试这段代码,添加import PlaygroundSupport到你的游乐场,以及下面的调用:
PlaygroundPage.current.needsIndefiniteExecution = true
这将允许你在操场上使用异步代码。
另一个选择是Alamofire库,它提供了可链请求/响应方法。
https://github.com/Alamofire/Alamofire
提出请求
import Alamofire
Alamofire.request(.GET, "http://httpbin.org/get")
响应处理
Alamofire.request(.GET, "http://httpbin.org/get", parameters: ["foo": "bar"])
.response { request, response, data, error in
print(request)
print(response)
print(error)
}
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