我有一个很长的ListView,用户可以在返回前一个屏幕之前滚动它。当用户再次打开这个ListView时,我希望列表被滚动到与之前相同的位置。关于如何实现这一点,你有什么想法吗?
当前回答
警告! !在AbsListView中有一个错误,如果ListView.getFirstVisiblePosition()为0,则不允许onSaveState()正确工作。
所以,如果你有大图像,占据了屏幕的大部分,你滚动到第二张图像,但第一张图像的一部分正在显示,滚动位置将不会被保存…
从AbsListView.java:1650(评论我)
// this will be false when the firstPosition IS 0
if (haveChildren && mFirstPosition > 0) {
...
} else {
ss.viewTop = 0;
ss.firstId = INVALID_POSITION;
ss.position = 0;
}
但在这种情况下,下面代码中的“top”将是一个负数,这将导致其他问题,阻止状态被正确恢复。所以当'top'为负时,就得到下一个子结点
// save index and top position
int index = getFirstVisiblePosition();
View v = getChildAt(0);
int top = (v == null) ? 0 : v.getTop();
if (top < 0 && getChildAt(1) != null) {
index++;
v = getChildAt(1);
top = v.getTop();
}
// parcel the index and top
// when restoring, unparcel index and top
listView.setSelectionFromTop(index, top);
其他回答
如果你在一个活动上使用片段,你可以这样做:
public abstract class BaseFragment extends Fragment {
private boolean mSaveView = false;
private SoftReference<View> mViewReference;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
if (mSaveView) {
if (mViewReference != null) {
final View savedView = mViewReference.get();
if (savedView != null) {
if (savedView.getParent() != null) {
((ViewGroup) savedView.getParent()).removeView(savedView);
return savedView;
}
}
}
}
final View view = inflater.inflate(getFragmentResource(), container, false);
mViewReference = new SoftReference<View>(view);
return view;
}
protected void setSaveView(boolean value) {
mSaveView = value;
}
}
public class MyFragment extends BaseFragment {
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
setSaveView(true);
final View view = super.onCreateView(inflater, container, savedInstanceState);
ListView placesList = (ListView) view.findViewById(R.id.places_list);
if (placesList.getAdapter() == null) {
placesList.setAdapter(createAdapter());
}
}
}
我采用了@(Kirk Woll)建议的解决方案,它对我很有效。我还在“联系人”应用程序的Android源代码中看到,他们使用了类似的技术。我还想补充一些具体情况: 在我的listactivity派生类的顶部:
private static final String LIST_STATE = "listState";
private Parcelable mListState = null;
然后,一些方法重写:
@Override
protected void onRestoreInstanceState(Bundle state) {
super.onRestoreInstanceState(state);
mListState = state.getParcelable(LIST_STATE);
}
@Override
protected void onResume() {
super.onResume();
loadData();
if (mListState != null)
getListView().onRestoreInstanceState(mListState);
mListState = null;
}
@Override
protected void onSaveInstanceState(Bundle state) {
super.onSaveInstanceState(state);
mListState = getListView().onSaveInstanceState();
state.putParcelable(LIST_STATE, mListState);
}
当然,“loadData”是我从DB中检索数据并将其放入列表的函数。
在我的Froyo设备上,当你改变手机方向时,当你编辑一个项目并返回列表时,这都是有效的。
Parcelable state;
@Override
public void onPause() {
// Save ListView state @ onPause
Log.d(TAG, "saving listview state");
state = listView.onSaveInstanceState();
super.onPause();
}
...
@Override
public void onViewCreated(final View view, Bundle savedInstanceState) {
super.onViewCreated(view, savedInstanceState);
// Set new items
listView.setAdapter(adapter);
...
// Restore previous state (including selected item index and scroll position)
if(state != null) {
Log.d(TAG, "trying to restore listview state");
listView.onRestoreInstanceState(state);
}
}
我的答案是Firebase和位置0是一个变通办法
Parcelable state;
DatabaseReference everybody = db.getReference("Everybody Room List");
everybody.addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
state = listView.onSaveInstanceState(); // Save
progressBar.setVisibility(View.GONE);
arrayList.clear();
for (DataSnapshot messageSnapshot : dataSnapshot.getChildren()) {
Messages messagesSpacecraft = messageSnapshot.getValue(Messages.class);
arrayList.add(messagesSpacecraft);
}
listView.setAdapter(convertView);
listView.onRestoreInstanceState(state); // Restore
}
@Override
public void onCancelled(@NonNull DatabaseError databaseError) {
}
});
和convertView
位置0 a添加一个您不使用的空白项
public class Chat_ConvertView_List_Room extends BaseAdapter {
private ArrayList<Messages> spacecrafts;
private Context context;
@SuppressLint("CommitPrefEdits")
Chat_ConvertView_List_Room(Context context, ArrayList<Messages> spacecrafts) {
this.context = context;
this.spacecrafts = spacecrafts;
}
@Override
public int getCount() {
return spacecrafts.size();
}
@Override
public Object getItem(int position) {
return spacecrafts.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
@SuppressLint({"SetTextI18n", "SimpleDateFormat"})
@Override
public View getView(final int position, View convertView, ViewGroup parent) {
if (convertView == null) {
convertView = LayoutInflater.from(context).inflate(R.layout.message_model_list_room, parent, false);
}
final Messages s = (Messages) this.getItem(position);
if (position == 0) {
convertView.getLayoutParams().height = 1; // 0 does not work
} else {
convertView.getLayoutParams().height = RelativeLayout.LayoutParams.WRAP_CONTENT;
}
return convertView;
}
}
我已经看到这个工作暂时不打扰用户,我希望它为您工作
使用下面的代码:
int index,top;
@Override
protected void onPause() {
super.onPause();
index = mList.getFirstVisiblePosition();
View v = challengeList.getChildAt(0);
top = (v == null) ? 0 : (v.getTop() - mList.getPaddingTop());
}
无论何时你刷新你的数据使用下面的代码:
adapter.notifyDataSetChanged();
mList.setSelectionFromTop(index, top);
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