我试图使用Node.js获取目录中所有文件的名称列表。我希望输出文件名数组。我该怎么做?
当前回答
如果有人:
只想列出项目本地子文件夹中的文件名(不包括目录)
✅ 无其他依赖项✅ 1功能✅ 规格化路径(Unix与Windows)
const fs = require("fs");
const path = require("path");
/**
* @param {string} relativeName "resources/foo/goo"
* @return {string[]}
*/
const listFileNames = (relativeName) => {
try {
const folderPath = path.join(process.cwd(), ...relativeName.split("/"));
return fs
.readdirSync(folderPath, { withFileTypes: true })
.filter((dirent) => dirent.isFile())
.map((dirent) => dirent.name.split(".")[0]);
} catch (err) {
// ...
}
};
README.md
package.json
resources
|-- countries
|-- usa.yaml
|-- japan.yaml
|-- gb.yaml
|-- provinces
|-- .........
listFileNames("resources/countries") #=> ["usa", "japan", "gb"]
其他回答
这将起作用,并将结果存储在test.txt文件中,该文件将位于同一目录中
fs.readdirSync(__dirname).forEach(file => {
fs.appendFileSync("test.txt", file+"\n", function(err){
})
})
如果有人:
只想列出项目本地子文件夹中的文件名(不包括目录)
✅ 无其他依赖项✅ 1功能✅ 规格化路径(Unix与Windows)
const fs = require("fs");
const path = require("path");
/**
* @param {string} relativeName "resources/foo/goo"
* @return {string[]}
*/
const listFileNames = (relativeName) => {
try {
const folderPath = path.join(process.cwd(), ...relativeName.split("/"));
return fs
.readdirSync(folderPath, { withFileTypes: true })
.filter((dirent) => dirent.isFile())
.map((dirent) => dirent.name.split(".")[0]);
} catch (err) {
// ...
}
};
README.md
package.json
resources
|-- countries
|-- usa.yaml
|-- japan.yaml
|-- gb.yaml
|-- provinces
|-- .........
listFileNames("resources/countries") #=> ["usa", "japan", "gb"]
这是一个异步递归版本。
function ( path, callback){
// the callback gets ( err, files) where files is an array of file names
if( typeof callback !== 'function' ) return
var
result = []
, files = [ path.replace( /\/\s*$/, '' ) ]
function traverseFiles (){
if( files.length ) {
var name = files.shift()
fs.stat(name, function( err, stats){
if( err ){
if( err.errno == 34 ) traverseFiles()
// in case there's broken symbolic links or a bad path
// skip file instead of sending error
else callback(err)
}
else if ( stats.isDirectory() ) fs.readdir( name, function( err, files2 ){
if( err ) callback(err)
else {
files = files2
.map( function( file ){ return name + '/' + file } )
.concat( files )
traverseFiles()
}
})
else{
result.push(name)
traverseFiles()
}
})
}
else callback( null, result )
}
traverseFiles()
}
function getFilesRecursiveSync(dir, fileList, optionalFilterFunction) {
if (!fileList) {
grunt.log.error("Variable 'fileList' is undefined or NULL.");
return;
}
var files = fs.readdirSync(dir);
for (var i in files) {
if (!files.hasOwnProperty(i)) continue;
var name = dir + '/' + files[i];
if (fs.statSync(name).isDirectory()) {
getFilesRecursiveSync(name, fileList, optionalFilterFunction);
} else {
if (optionalFilterFunction && optionalFilterFunction(name) !== true)
continue;
fileList.push(name);
}
}
}
采用@湖南罗斯托米扬的一般方法,使其更加简洁,并添加了excludeDirs论点。使用includeDirs进行扩展很简单,只需遵循相同的模式:
import * as fs from 'fs';
import * as path from 'path';
function fileList(dir, excludeDirs?) {
return fs.readdirSync(dir).reduce(function (list, file) {
const name = path.join(dir, file);
if (fs.statSync(name).isDirectory()) {
if (excludeDirs && excludeDirs.length) {
excludeDirs = excludeDirs.map(d => path.normalize(d));
const idx = name.indexOf(path.sep);
const directory = name.slice(0, idx === -1 ? name.length : idx);
if (excludeDirs.indexOf(directory) !== -1)
return list;
}
return list.concat(fileList(name, excludeDirs));
}
return list.concat([name]);
}, []);
}
示例用法:
console.log(fileList('.', ['node_modules', 'typings', 'bower_components']));