我想要一个bash命令，我可以管道将一列数字相加。我只是想要一个快速的一行程序，基本上是这样做的:
cat FileWithColumnOfNumbers.txt | sum
当前回答
[ghostdog74s评论的后续]
bash-2.03$ uname -sr
SunOS 5.8
bash-2.03$ perl -le 'print for 1..49999998' > infile
bash-2.03$ wc -l infile
49999998 infile
bash-2.03$ time paste -sd+ infile | bc
bundling space exceeded on line 1, teletype
Broken Pipe
real 0m0.062s
user 0m0.010s
sys 0m0.010s
bash-2.03$ time nawk '{s+=$1}END{print s}' infile
1249999925000001
real 2m0.042s
user 1m59.220s
sys 0m0.590s
bash-2.03$ time /usr/xpg4/bin/awk '{s+=$1}END{print s}' infile
1249999925000001
real 2m27.260s
user 2m26.230s
sys 0m0.660s
bash-2.03$ time perl -nle'
$s += $_; END { print $s }
' infile
1.249999925e+15
real 1m34.663s
user 1m33.710s
sys 0m0.650s
其他回答
[ghostdog74s评论的后续]
bash-2.03$ uname -sr
SunOS 5.8
bash-2.03$ perl -le 'print for 1..49999998' > infile
bash-2.03$ wc -l infile
49999998 infile
bash-2.03$ time paste -sd+ infile | bc
bundling space exceeded on line 1, teletype
Broken Pipe
real 0m0.062s
user 0m0.010s
sys 0m0.010s
bash-2.03$ time nawk '{s+=$1}END{print s}' infile
1249999925000001
real 2m0.042s
user 1m59.220s
sys 0m0.590s
bash-2.03$ time /usr/xpg4/bin/awk '{s+=$1}END{print s}' infile
1249999925000001
real 2m27.260s
user 2m26.230s
sys 0m0.660s
bash-2.03$ time perl -nle'
$s += $_; END { print $s }
' infile
1.249999925e+15
real 1m34.663s
user 1m33.710s
sys 0m0.650s
使用现有文件:
paste -sd+ infile | bc
使用stdin:
<cmd> | paste -sd+ | bc
编辑: 对于一些粘贴实现，你需要更明确地从stdin读取:
<cmd> |粘贴-sd+ - | BC
选择使用:
-s (serial) -将所有行合并为一行 -d -使用非默认分隔符(在本例中为字符+)
如果你安装了ruby
cat FileWithColumnOfNumbers.txt | xargs ruby -e "puts ARGV.map(&:to_i).inject(&:+)"
while read -r num; do ((sum += num)); done < inputfile; echo $sum
使用for循环遍历你的文件…
sum=0; for x in `cat <your-file>`; do let sum+=x; done; echo $sum
