我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
当前回答
我已经在这里解释过了 把答案也粘贴到这里
在23:59:59小时之前,您可以使用PHP默认函数
echo gmdate("H:i:s", 86399);
只会返回结果直到23:59:59
如果你的秒数大于86399 在@VolkerK的帮助下回答
$time = round($seconds);
echo sprintf('%02d:%02d:%02d', ($time/3600),($time/60%60), $time%60);
将是使用…的最佳选择。
其他回答
写这样的函数返回一个数组
function secondsToTime($seconds) {
// extract hours
$hours = floor($seconds / (60 * 60));
// extract minutes
$divisor_for_minutes = $seconds % (60 * 60);
$minutes = floor($divisor_for_minutes / 60);
// extract the remaining seconds
$divisor_for_seconds = $divisor_for_minutes % 60;
$seconds = ceil($divisor_for_seconds);
// return the final array
$obj = array(
"h" => (int) $hours,
"m" => (int) $minutes,
"s" => (int) $seconds,
);
return $obj;
}
然后像这样简单地调用函数:
secondsToTime(100);
输出是
Array ( [h] => 0 [m] => 1 [s] => 40 )
如果你不喜欢公认的答案或流行的答案,那么试试这个
function secondsToTime($seconds_time)
{
if ($seconds_time < 24 * 60 * 60) {
return gmdate('H:i:s', $seconds_time);
} else {
$hours = floor($seconds_time / 3600);
$minutes = floor(($seconds_time - $hours * 3600) / 60);
$seconds = floor($seconds_time - ($hours * 3600) - ($minutes * 60));
return "$hours:$minutes:$seconds";
}
}
secondsToTime(108620); // 30:10:20
function timeToSecond($time){
$time_parts=explode(":",$time);
$seconds= ($time_parts[0]*86400) + ($time_parts[1]*3600) + ($time_parts[2]*60) + $time_parts[3] ;
return $seconds;
}
function secondToTime($time){
$seconds = $time % 60;
$seconds<10 ? "0".$seconds : $seconds;
if($seconds<10) {
$seconds="0".$seconds;
}
$time = ($time - $seconds) / 60;
$minutes = $time % 60;
if($minutes<10) {
$minutes="0".$minutes;
}
$time = ($time - $minutes) / 60;
$hours = $time % 24;
if($hours<10) {
$hours="0".$hours;
}
$days = ($time - $hours) / 24;
if($days<10) {
$days="0".$days;
}
$time_arr = array($days,$hours,$minutes,$seconds);
return implode(":",$time_arr);
}
这个函数是有用的,你可以扩展它:
function formatSeconds($seconds) {
if(!is_integer($seconds)) {
return FALSE;
}
$fmt = "";
$days = floor($seconds / 86400);
if($days) {
$fmt .= $days."D ";
$seconds %= 86400;
}
$hours = floor($seconds / 3600);
if($hours) {
$fmt .= str_pad($hours, 2, '0', STR_PAD_LEFT).":";
$seconds %= 3600;
}
$mins = floor($seconds / 60 );
if($mins) {
$fmt .= str_pad($mins, 2, '0', STR_PAD_LEFT).":";
$seconds %= 60;
}
$fmt .= str_pad($seconds, 2, '0', STR_PAD_LEFT);
return $fmt;}
解决方案来自:https://gist.github.com/SteveJobzniak/c91a8e2426bac5cb9b0cbc1bdbc45e4b
这段代码尽可能地避免了乏味的函数调用和逐条的字符串构建,以及人们为此而创建的大而笨重的函数。
它返回格式为“1h05m00s”的输出,并使用前导零表示分和秒,只要在它们之前有另一个非零时间组件。
它还跳过所有空的前导组件,以避免给你无用的信息,如“0h00m01s”(相反,它将显示为“1s”)。
示例结果:“1s”、“1m00s”、“19m08s”、“1h00m00s”、“4h08m39s”。
$duration = 1; // values 0 and higher are supported!
$converted = [
'hours' => floor( $duration / 3600 ),
'minutes' => floor( ( $duration / 60 ) % 60 ),
'seconds' => ( $duration % 60 )
];
$result = ltrim( sprintf( '%02dh%02dm%02ds', $converted['hours'], $converted['minutes'], $converted['seconds'] ), '0hm' );
if( $result == 's' ) { $result = '0s'; }
如果你想让代码更短(但可读性更差),你可以避免$转换数组,而是直接将值放在sprintf()调用中,如下所示:
$duration = 1; // values 0 and higher are supported!
$result = ltrim( sprintf( '%02dh%02dm%02ds', floor( $duration / 3600 ), floor( ( $duration / 60 ) % 60 ), ( $duration % 60 ) ), '0hm' );
if( $result == 's' ) { $result = '0s'; }
在上面的两个代码段中,持续时间必须为0或更高。不支持负持续时间。但是你可以使用下面的代码来处理负持续时间:
$duration = -493; // negative values are supported!
$wasNegative = FALSE;
if( $duration < 0 ) { $wasNegative = TRUE; $duration = abs( $duration ); }
$converted = [
'hours' => floor( $duration / 3600 ),
'minutes' => floor( ( $duration / 60 ) % 60 ),
'seconds' => ( $duration % 60 )
];
$result = ltrim( sprintf( '%02dh%02dm%02ds', $converted['hours'], $converted['minutes'], $converted['seconds'] ), '0hm' );
if( $result == 's' ) { $result = '0s'; }
if( $wasNegative ) { $result = "-{$result}"; }
// $result is now "-8m13s"