我的布局中有一个EditText和一个Button。

在编辑字段中写入并单击按钮后,我想在触摸键盘外部时隐藏虚拟键盘。我假设这是一段简单的代码,但我在哪里可以找到它的示例?


当前回答

首先,您应该从XML文件中添加addandroid:imeOptions字段,并将其值更改为actionUnspecified|actionGo,如下所示

 <android.support.design.widget.TextInputEditText
                    android:id="@+id/edit_text_id"
                    android:layout_width="fill_parent"
                    android:layout_height="@dimen/edit_text_height"
                    android:imeOptions="actionUnspecified|actionGo"
                    />

然后在java类中添加setOnEditorActionListener并添加InputMethodManager,如下所示

enterOrderNumber.setOnEditorActionListener(新的TextView.OnEditorActionlister(){

    @Override
    public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
        if (actionId == EditorInfo.IME_ACTION_GO) {
            InputMethodManager imm = (InputMethodManager) getActivity().getSystemService(Activity.INPUT_METHOD_SERVICE);
            imm.toggleSoftInput(InputMethodManager.HIDE_IMPLICIT_ONLY, 0);
            return true;
        }
        return false;
    }
});

其他回答

感谢上帝,它在11年后得到了官方支持

首先将依赖实现“androidx.core:core-ktx:1.7.0”添加到appgradle

然后从ViewCompat或WindowCompat类获取InsetsController。

最后使用InsetsController的hide()和show()函数

已编辑添加对Dialog的支持。在BottomSheetDialog中提供@隆德夫。使用更安全的方式获取活动,而不是直接从上下文中强制转换。

import android.app.Activity
import android.app.Dialog
import android.content.Context
import android.content.ContextWrapper
import android.view.View
import androidx.core.view.ViewCompat
import androidx.core.view.WindowCompat
import androidx.core.view.WindowInsetsCompat
import androidx.fragment.app.Fragment

fun View.showKeyboard() = ViewCompat.getWindowInsetsController(this)?.show(WindowInsetsCompat.Type.ime())
fun View.hideKeyboard() = ViewCompat.getWindowInsetsController(this)?.hide(WindowInsetsCompat.Type.ime())

fun Dialog.showKeyboard() = window?.decorView?.showKeyboard()
fun Dialog.hideKeyboard() = window?.decorView?.hideKeyboard()

fun Context.showKeyboard() = getActivity()?.showKeyboard()
fun Context.hideKeyboard() = getActivity()?.hideKeyboard()

fun Fragment.showKeyboard() = activity?.showKeyboard()
fun Fragment.hideKeyboard() = activity?.hideKeyboard()

fun Activity.showKeyboard() = WindowCompat.getInsetsController(window, window.decorView)?.show(WindowInsetsCompat.Type.ime())
fun Activity.hideKeyboard() = WindowCompat.getInsetsController(window, window.decorView)?.hide(WindowInsetsCompat.Type.ime())

fun Context.getActivity(): Activity? {
    return when (this) {
        is Activity -> this
        is ContextWrapper -> this.baseContext.getActivity()
        else -> null
    }
}

下面是旧的anwser

下面是github上的简单项目

import android.app.Activity
import android.app.Dialog
import android.content.Context
import android.content.ContextWrapper
import android.view.View
import androidx.core.view.ViewCompat
import androidx.core.view.WindowCompat
import androidx.core.view.WindowInsetsCompat
import androidx.fragment.app.Fragment

fun View.showKeyboard() = ViewCompat.getWindowInsetsController(this)?.show(WindowInsetsCompat.Type.ime())
fun View.hideKeyboard() = ViewCompat.getWindowInsetsController(this)?.hide(WindowInsetsCompat.Type.ime())

fun Dialog.showKeyboard() = window?.decorView?.showKeyboard()
fun Dialog.hideKeyboard() = window?.decorView?.hideKeyboard()

fun Context.showKeyboard() = getActivity()?.showKeyboard()
fun Context.hideKeyboard() = getActivity()?.hideKeyboard()

fun Fragment.showKeyboard() = activity?.showKeyboard()
fun Fragment.hideKeyboard() = activity?.hideKeyboard()

fun Activity.showKeyboard() = WindowCompat.getInsetsController(window, window.decorView)?.show(WindowInsetsCompat.Type.ime())
fun Activity.hideKeyboard() = WindowCompat.getInsetsController(window, window.decorView)?.hide(WindowInsetsCompat.Type.ime())

fun Context.getActivity(): Activity? {
    return when (this) {
        is Activity -> this
        is ContextWrapper -> this.baseContext.getActivity()
        else -> null
    }
}

请在onCreate()中尝试以下代码

EditText edtView = (EditText) findViewById(R.id.editTextConvertValue);
edtView.setInputType(InputType.TYPE_NULL);

简短的回答

在OnClick监听器中,使用IME_ACTION_DONE调用EditText的onEditorAction

button.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View v) {
        someEditText.onEditorAction(EditorInfo.IME_ACTION_DONE)
    }
});

向下钻取

我觉得这种方法更好,更简单,更符合Android的设计模式。在上面的简单示例中(通常在大多数常见情况下),您将拥有一个具有焦点的EditText,并且它通常也是首先调用键盘的一个(在许多常见情况下它肯定能够调用它)。以同样的方式,它应该是释放键盘的人,通常这可以通过ImeAction来完成。只要看看带有android:imeOptions=“actionDone”的EditText的行为,您就可以通过相同的方式实现相同的行为。


检查此相关答案

对于开放式键盘:

InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
imm.showSoftInput(edtView, InputMethodManager.SHOW_IMPLICIT);

对于关闭/隐藏键盘:

 InputMethodManager imm = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
 imm.hideSoftInputFromWindow(edtView.getWindowToken(), 0);

简单编码:在onCreate()中使用此代码

getWindow().setSoftInputMode(
    WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_HIDDEN
);