如何获取mysql数据库的大小? 假设目标数据库名为“v3”。
当前回答
运行这个查询,你可能会得到你想要的:
SELECT table_schema "DB Name",
ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables
GROUP BY table_schema;
这个查询来自mysql论坛,那里有更全面的说明可用。
其他回答
运行这个查询,你可能会得到你想要的:
SELECT table_schema "DB Name",
ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables
GROUP BY table_schema;
这个查询来自mysql论坛,那里有更全面的说明可用。
可以使用下面的MySQL命令来确定
SELECT table_schema AS "Database", SUM(data_length + index_length) / 1024 / 1024 AS "Size (MB)" FROM information_schema.TABLES GROUP BY table_schema
结果
Database Size (MB)
db1 11.75678253
db2 9.53125000
test 50.78547382
以GB为单位获取结果
SELECT table_schema AS "Database", SUM(data_length + index_length) / 1024 / 1024 / 1024 AS "Size (GB)" FROM information_schema.TABLES GROUP BY table_schema
另外:如果有人想获取单个表的大小,请使用以下代码:
SELECT
TABLE_NAME AS `Table Name`,
ROUND((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024) AS `Size ( in MB)`
FROM
information_schema.TABLES
WHERE
TABLE_SCHEMA = "your_db_name"
AND
TABLE_NAME = "your_single_table_name"
ORDER BY
(DATA_LENGTH + INDEX_LENGTH)
DESC;
注意:它不会显示使用ROUND()方法的分数。
希望这能对我们中的许多人有所帮助。
如果你想要排序所有数据库大小的列表,你可以使用:
SELECT *
FROM (SELECT table_schema AS `DB Name`,
ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) AS `DB Size in MB`
FROM information_schema.tables
GROUP BY `DB Name`) AS tmp_table
ORDER BY `DB Size in MB` DESC;
或者,您可以直接跳转到数据目录并检查v3的组合大小。myd, v3。Myi和v3。FRM文件(用于myisam)或v3。Idb & v3.frm(用于innodb)。