下面是一个测试驱动的通用方法。虽然不像目前提供的大多数解决方案那样“高效”，但是清晰、经过测试、有效且通用。

public class CountBooleansTest extends TestCase {
    public void testThreeFalse() throws Exception {
        assertFalse(atLeastTwoOutOfThree(false, false, false));
    }

    public void testThreeTrue() throws Exception {
        assertTrue(atLeastTwoOutOfThree(true, true, true));
    }

    public void testOnes() throws Exception {
        assertFalse(atLeastTwoOutOfThree(true, false, false));
        assertFalse(atLeastTwoOutOfThree(false, true, false));
        assertFalse(atLeastTwoOutOfThree(false, false, true));
    }

    public void testTwos() throws Exception {
        assertTrue(atLeastTwoOutOfThree(false, true, true));
        assertTrue(atLeastTwoOutOfThree(true, false, true));
        assertTrue(atLeastTwoOutOfThree(true, true, false));
    }

    private static boolean atLeastTwoOutOfThree(boolean b, boolean c, boolean d) {
        return countBooleans(b, c, d) >= 2;
    }

    private static int countBooleans(boolean... bs) {
        int count = 0;
        for (boolean b : bs)
            if (b)
                count++;
        return count;
    }
}

我找到了这个解。

boolean atLeastTwo(boolean a, boolean b, boolean c) {
    bool result = !(a ^ b ^ c) && !(!a & !b & !c) || (a & b & c);
    return result;
}

One thing I haven't seen others point out is that a standard thing to do in the "please write me some code" section of the job interview is to say "Could you improve that?" or "Are you completely happy with that" or "is that as optimized as possible?" when you say you are done. It's possible you heard "how would you improve that" as "this might be improved; how?". In this case changing the if(x) return true; else return false; idiom to just return x is an improvement - but be aware that there are times they just want to see how you react to the question. I have heard that some interviewers will insist there is a flaw in perfect code just to see how you cope with it.

通过真值表计算:

return (a & b) | (c & (a ^ b));

另一个:

return a? b||c : b&&c

int count=0;

boolean atLeastTwo(boolean a, boolean b, boolean c) {
    if (a)
        count++;
    if (b)
        count++;
    if (c)
        count++;

    if (count>1)
        return true;
    else
        return false;
}