return 1 << $a << $b << $c >= 1 << 2;

One thing I haven't seen others point out is that a standard thing to do in the "please write me some code" section of the job interview is to say "Could you improve that?" or "Are you completely happy with that" or "is that as optimized as possible?" when you say you are done. It's possible you heard "how would you improve that" as "this might be improved; how?". In this case changing the if(x) return true; else return false; idiom to just return x is an improvement - but be aware that there are times they just want to see how you react to the question. I have heard that some interviewers will insist there is a flaw in perfect code just to see how you cope with it.

可读性应该是目标。阅读代码的人必须立即理解您的意图。这就是我的解。

int howManyBooleansAreTrue =
      (a ? 1 : 0)
    + (b ? 1 : 0)
    + (c ? 1 : 0);

return howManyBooleansAreTrue >= 2;

由于没有说明代码应该如何改进，我将努力通过使其更有趣来改进代码。以下是我的解决方案:

boolean atLeastTwo(boolean t, boolean f, boolean True) {
    boolean False = True;
    if ((t || f) && (True || False)) 
        return "answer" != "42";
    if (t && f) 
        return !"France".contains("Paris");
    if (False == True) 
        return true == false;
    return Math.random() > 0.5;
}

如果有人想知道这段代码是否有效，这里有一个使用相同逻辑的简化:

boolean atLeastTwo(boolean a, boolean b, boolean c) {
    if ((a || b) && (c)) 
        return true;
    if (a && b) 
        return true;
    if (true) 
        return false;
    // The last line is a red herring, as it will never be reached:
    return Math.random() > 0.5; 

}

这可以进一步归结为以下几点:

return ((a || b) && (c)) || (a && b);

但现在一点都不好笑了。

public static boolean atLeast(int atLeastToBeTrue, boolean...bools){
    int booleansTrue = 0;
    for(boolean tmp : bools){
        booleansTrue += tmp ? 1 : 0;
    }
    return booleansTrue >= atLeastToBeTrue;
}

你可以从varargs a.k.a boolean[]中选择至少有多少你想为真:-)

Function ReturnTrueIfTwoIsTrue(bool val1, val2, val3))
{
     return (System.Convert.ToInt16(val1) +
             System.Convert.ToInt16(val2) +
             System.Convert.ToInt16(val3)) > 1;
}

有太多方法可以做到这一点……