下面是发送HTML电子邮件的简单方法，只需指定Content-Type头为'text/ HTML ':

import email.message
import smtplib

msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = 'sender@test.com'
msg['To'] = 'recipient@test.com'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
        email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()

实际上，yagmail采取了一点不同的方法。

它将在默认情况下发送HTML，并为无法阅读电子邮件的用户提供自动回退功能。现在已经不是17世纪了。

当然，它可以被覆盖，但如下所示:

import yagmail
yag = yagmail.SMTP("me@example.com", "mypassword")

html_msg = """<p>Hi!<br>
              How are you?<br>
              Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""

yag.send("to@example.com", "the subject", html_msg)

有关安装说明和更多伟大的功能，请查看github。

下面是发送HTML电子邮件的简单方法，只需指定Content-Type头为'text/ HTML ':

import email.message
import smtplib

msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = 'sender@test.com'
msg['To'] = 'recipient@test.com'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
        email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()

我在这里提供答案可能有点晚了，但是这个问题询问了一种发送HTML电子邮件的方法。使用像“email”这样的专用模块是可以的，但我们可以在不使用任何新模块的情况下实现相同的结果。这都归结为Gmail协议。

下面是我的简单示例代码，仅通过使用“smtplib”发送HTML邮件，而不使用其他任何代码。

```
import smtplib

FROM = "....@gmail.com"
TO = "another....@gmail.com"
SUBJECT= "Subject"
PWD = "thesecretkey"

TEXT="""
<h1>Hello</h1>
""" #Your Message (Even Supports HTML Directly)

message = f"Subject: {SUBJECT}\nFrom: {FROM}\nTo: {TO}\nContent-Type: text/html\n\n{TEXT}" #This is where the stuff happens

try:
    server=smtplib.SMTP("smtp.gmail.com",587)
    server.ehlo()
    server.starttls()
    server.login(FROM,PWD)
    server.sendmail(FROM,TO,message)
    server.close()
    print("Successfully sent the mail.")
except Exception as e:
    print("Failed to send the mail..", e)
```

你可以试试我的邮件模块。

from mailer import Mailer
from mailer import Message

message = Message(From="me@example.com",
                  To="you@example.com")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
   How are you?<br>
   Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""

sender = Mailer('smtp.example.com')
sender.send(message)

下面是示例代码。灵感来自Python Cookbook网站上的代码(找不到确切的链接)

def createhtmlmail (html, text, subject, fromEmail):
    """Create a mime-message that will render HTML in popular
    MUAs, text in better ones"""
    import MimeWriter
    import mimetools
    import cStringIO

    out = cStringIO.StringIO() # output buffer for our message 
    htmlin = cStringIO.StringIO(html)
    txtin = cStringIO.StringIO(text)

    writer = MimeWriter.MimeWriter(out)
    #
    # set up some basic headers... we put subject here
    # because smtplib.sendmail expects it to be in the
    # message body
    #
    writer.addheader("From", fromEmail)
    writer.addheader("Subject", subject)
    writer.addheader("MIME-Version", "1.0")
    #
    # start the multipart section of the message
    # multipart/alternative seems to work better
    # on some MUAs than multipart/mixed
    #
    writer.startmultipartbody("alternative")
    writer.flushheaders()
    #
    # the plain text section
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
    mimetools.encode(txtin, pout, 'quoted-printable')
    txtin.close()
    #
    # start the html subpart of the message
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    #
    # returns us a file-ish object we can write to
    #
    pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
    mimetools.encode(htmlin, pout, 'quoted-printable')
    htmlin.close()
    #
    # Now that we're done, close our writer and
    # return the message body
    #
    writer.lastpart()
    msg = out.getvalue()
    out.close()
    print msg
    return msg

if __name__=="__main__":
    import smtplib
    html = 'html version'
    text = 'TEST VERSION'
    subject = "BACKUP REPORT"
    message = createhtmlmail(html, text, subject, 'From Host <sender@host.com>')
    server = smtplib.SMTP("smtp_server_address","smtp_port")
    server.login('username', 'password')
    server.sendmail('sender@host.com', 'target@otherhost.com', message)
    server.quit()