如果你想看第7行

line = open("file.txt", "r").readlines()[7]

如果要读取的文件很大，并且你不想一次在内存中读取整个文件:

fp = open("file")
for i, line in enumerate(fp):
    if i == 25:
        # 26th line
    elif i == 29:
        # 30th line
    elif i > 29:
        break
fp.close()

注意第n行i == n-1。

在Python 2.6或更高版本中:

with open("file") as fp:
    for i, line in enumerate(fp):
        if i == 25:
            # 26th line
        elif i == 29:
            # 30th line
        elif i > 29:
            break

从某一行读出:

n = 4   # for reading from 5th line
with open("write.txt",'r') as t:
     for i,line in enumerate(t):
         if i >= n:             # i == n-1 for nth line
            print(line)

@OP，你可以使用枚举

for n,line in enumerate(open("file")):
    if n+1 in [26,30]: # or n in [25,29] 
       print line.rstrip()

文件对象有一个.readlines()方法，它将为您提供文件内容的列表，每个列表项一行。在此之后，您可以使用普通的列表切片技术。

http://docs.python.org/library/stdtypes.html#file.readlines

这个怎么样:

>>> with open('a', 'r') as fin: lines = fin.readlines()
>>> for i, line in enumerate(lines):
      if i > 30: break
      if i == 26: dox()
      if i == 30: doy()