使用StreamEx库，您可以使用StreamEx。ofSubLists(List<T> source, int length)方法:

返回一个新的StreamEx，它由给定源列表的不重叠子列表组成，具有指定的长度(最后一个子列表可能更短)。

// Assuming you don't actually care that the lists are of type ArrayList
List<List<Integer>> sublists = StreamEx.ofSubLists(result, 10).toList();

// If you actually want them to be of type ArrayList, per your question
List<List<Integer>> sublists = StreamEx.ofSubLists(result, 10).toCollection(ArrayList::new);

如果你不想导入apache Commons库，试试下面这段简单的代码:

final static int MAX_ELEMENT = 20;

public static void main(final String[] args) {

    final List<String> list = new ArrayList<String>();

    for (int i = 1; i <= 161; i++) {
        list.add(String.valueOf(i));
        System.out.print("," + String.valueOf(i));
    }
    System.out.println("");
    System.out.println("### >>> ");
    final List<List<String>> result = splitList(list, MAX_ELEMENT);

    for (final List<String> entry : result) {
        System.out.println("------------------------");
        for (final String elm : entry) {
            System.out.println(elm);
        }
        System.out.println("------------------------");
    }

}

private static List<List<String>> splitList(final List<String> list, final int maxElement) {

    final List<List<String>> result = new ArrayList<List<String>>();

    final int div = list.size() / maxElement;

    System.out.println(div);

    for (int i = 0; i <= div; i++) {

        final int startIndex = i * maxElement;

        if (startIndex >= list.size()) {
            return result;
        }

        final int endIndex = (i + 1) * maxElement;

        if (endIndex < list.size()) {
            result.add(list.subList(startIndex, endIndex));
        } else {
            result.add(list.subList(startIndex, list.size()));
        }

    }

    return result;
}

polygenelubricants提供的答案将基于给定数组的大小。我正在寻找将数组分割成给定数量的部分的代码。以下是我对代码所做的修改:

public static <T>List<List<T>> chopIntoParts( final List<T> ls, final int iParts )
{
    final List<List<T>> lsParts = new ArrayList<List<T>>();
    final int iChunkSize = ls.size() / iParts;
    int iLeftOver = ls.size() % iParts;
    int iTake = iChunkSize;

    for( int i = 0, iT = ls.size(); i < iT; i += iTake )
    {
        if( iLeftOver > 0 )
        {
            iLeftOver--;

            iTake = iChunkSize + 1;
        }
        else
        {
            iTake = iChunkSize;
        }

        lsParts.add( new ArrayList<T>( ls.subList( i, Math.min( iT, i + iTake ) ) ) );
    }

    return lsParts;
}

希望它能帮助到别人。

你可以使用Eclipse Collections中的chunk方法:

ArrayList<Integer> list = new ArrayList<>(Interval.oneTo(1000));
RichIterable<RichIterable<Integer>> chunks = Iterate.chunk(list, 10);
Verify.assertSize(100, chunks);

这篇DZone文章中还包含了一些块方法的示例。

注意:我是Eclipse Collections的提交者。

让我们假设您想要将列表分割为多个块的类作为库类。

所以让我们说这个类被称为“shared”，in应该是final，以确保它不会被扩展。

   import java.util.ArrayList;
   import java.util.Arrays;
   import java.util.List;

public final class Shared {
List<Integer> input;
int portion;

public Shared(int portion, Integer... input) {
    this.setPortion(portion);
    this.setInput(input);
}

public List<List<Integer>> listToChunks() {
    List<List<Integer>> result = new ArrayList<List<Integer>>();
    int size = this.size();
    int startAt = 0;
    int endAt = this.portion;

    while (endAt <= size) {

        result.add(this.input.subList(startAt, endAt));
        startAt = endAt;
        endAt = (size - endAt < this.portion && size - endAt > 0) ? (this.size()) : (endAt + this.portion);
    }

    return result;
}

public int size() {
    return this.input.size();
}

public void setInput(Integer... input) {
    if (input != null && input.length > 0)
        this.input = Arrays.asList(input);
    else
        System.out.println("Error 001 : please enter a valid array of integers.");
}

public void setPortion(int portion) {
    if (portion > 0)
        this.portion = portion;
    else
        System.out.println("Error 002 : please enter a valid positive number.");
}
}

接下来，让我们尝试从另一个持有公共静态void main(String…args)

public class exercise {

public static void main(String[] args) {
    Integer[] numbers = {1, 2, 3, 4, 5, 6, 7};
    int portion = 2;
    Shared share = new Shared(portion, numbers);
    System.out.println(share.listToChunks());   
}
}

现在，如果输入一个整数数组[1,2,3,4,5,6,7]，分区为2。 结果将是[[1,2]，[3,4]，[5,6]，[7]]

Apache Commons Collections 4在ListUtils类中有一个分区方法。下面是它的工作原理:

import org.apache.commons.collections4.ListUtils;
...

int targetSize = 100;
List<Integer> largeList = ...
List<List<Integer>> output = ListUtils.partition(largeList, targetSize);