我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。
我想知道是否有一种方法可以快速将它们全部更改为InnoDB?
我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。
我想知道是否有一种方法可以快速将它们全部更改为InnoDB?
当前回答
一个简单的MySQL版本。
你可以简单地启动mysql可执行文件,使用数据库和复制粘贴查询。
这将把当前数据库中的所有MyISAM表转换为INNODB表。
DROP PROCEDURE IF EXISTS convertToInnodb;
DELIMITER //
CREATE PROCEDURE convertToInnodb()
BEGIN
mainloop: LOOP
SELECT TABLE_NAME INTO @convertTable FROM information_schema.TABLES
WHERE `TABLE_SCHEMA` LIKE DATABASE()
AND `ENGINE` LIKE 'MyISAM' ORDER BY TABLE_NAME LIMIT 1;
IF @convertTable IS NULL THEN
LEAVE mainloop;
END IF;
SET @sqltext := CONCAT('ALTER TABLE `', DATABASE(), '`.`', @convertTable, '` ENGINE = INNODB');
PREPARE convertTables FROM @sqltext;
EXECUTE convertTables;
DEALLOCATE PREPARE convertTables;
SET @convertTable = NULL;
END LOOP mainloop;
END//
DELIMITER ;
CALL convertToInnodb();
DROP PROCEDURE IF EXISTS convertToInnodb;
其他回答
mysqli连接;
<?php
$host = "host";
$user = "user";
$pass = "pss";
$database = "db_name";
$connect = new mysqli($host, $user, $pass, $database);
// Actual code starts here Dont forget to change db_name !!
$sql = "SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'db_name'
AND ENGINE = 'MyISAM'";
$rs = $connect->query($sql);
while($row = $rs->fetch_array())
{
$tbl = $row[0];
$sql = "ALTER TABLE `$tbl` ENGINE=INNODB";
$connect->query($sql);
} ?>
试试这个shell脚本
DBENGINE='InnoDB' ;
DBUSER='your_db_user' ;
DBNAME='your_db_name' ;
DBHOST='your_db_host'
DBPASS='your_db_pass' ;
mysqldump --add-drop-table -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME > mtest.sql; mysql -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME -Nse "SHOW TABLES;" | while read TABLE ; do mysql -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME -Nse "ALTER TABLE $TABLE ENGINE=$DBENGINE;" ; done
当表很大时,最好从控制台进行操作
convert-to-innodb.sh
#!/usr/bin/env bash
# Usage: ./convert-to-innodb.sh 'db' 'user' 'password' | mysql 'db' -u user -p password
set -eu
db="$1"
user="$2"
pass="$3"
sql="SET @DATABASE_NAME = '${db}';"
sql+="SELECT CONCAT('ALTER TABLE \`', table_name, '\` ENGINE=InnoDB;') AS sql_statements
FROM information_schema.tables AS tb
WHERE table_schema = @DATABASE_NAME
AND \`ENGINE\` = 'MyISAM'
AND \`TABLE_TYPE\` = 'BASE TABLE'
ORDER BY table_name DESC;"
echo $sql | mysql -u${user} -p${pass} | tail -n +2
你可以在mysql命令行工具中执行这个语句:
echo "SELECT concat('ALTER TABLE `',TABLE_NAME,'` ENGINE=InnoDB;')
FROM Information_schema.TABLES
WHERE ENGINE != 'InnoDB' AND TABLE_TYPE='BASE TABLE'
AND TABLE_SCHEMA='name-of-database'" | mysql > convert.sql
您可能需要指定用户名和密码:mysql -u username -p 结果是一个sql脚本,你可以管道回mysql:
mysql name-of-database < convert.sql
替换上述语句和命令行中的"name-of-database"。
要为所有非系统模式中的所有表生成ALTER语句,按这些模式/表排序,运行以下命令:
SELECT CONCAT('ALTER TABLE ',TABLE_SCHEMA,'.', table_name, ' ENGINE=InnoDB;') AS sql_statements
FROM information_schema.tables
WHERE TABLE_SCHEMA NOT IN ('mysql', 'information_schema', 'performance_schema', 'innodb', 'sys', 'tmp')
AND `ENGINE` = 'MyISAM'
AND `TABLE_TYPE` = 'BASE TABLE'
ORDER BY TABLE_SCHEMA, table_name DESC;
之后,通过客户端运行这些查询来执行修改。
答案基于上述答案,但改进了模式处理。