我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。

我想知道是否有一种方法可以快速将它们全部更改为InnoDB?


当前回答

一个简单的MySQL版本。

你可以简单地启动mysql可执行文件,使用数据库和复制粘贴查询。

这将把当前数据库中的所有MyISAM表转换为INNODB表。

DROP PROCEDURE IF EXISTS convertToInnodb;
DELIMITER //
CREATE PROCEDURE convertToInnodb()
BEGIN
mainloop: LOOP
  SELECT TABLE_NAME INTO @convertTable FROM information_schema.TABLES
  WHERE `TABLE_SCHEMA` LIKE DATABASE()
  AND `ENGINE` LIKE 'MyISAM' ORDER BY TABLE_NAME LIMIT 1;
  IF @convertTable IS NULL THEN 
    LEAVE mainloop;
  END IF;
  SET @sqltext := CONCAT('ALTER TABLE `', DATABASE(), '`.`', @convertTable, '` ENGINE = INNODB');
  PREPARE convertTables FROM @sqltext;
  EXECUTE convertTables;
  DEALLOCATE PREPARE convertTables;
  SET @convertTable = NULL;
END LOOP mainloop;

END//
DELIMITER ;

CALL convertToInnodb();
DROP PROCEDURE IF EXISTS convertToInnodb;

其他回答

mysqli连接;

<?php

$host       = "host";
$user       = "user";
$pass       = "pss";
$database   = "db_name";


$connect = new mysqli($host, $user, $pass, $database);  

// Actual code starts here Dont forget to change db_name !!
$sql = "SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES
    WHERE TABLE_SCHEMA = 'db_name' 
    AND ENGINE = 'MyISAM'";

$rs = $connect->query($sql);

while($row = $rs->fetch_array())
{
    $tbl = $row[0];
    $sql = "ALTER TABLE `$tbl` ENGINE=INNODB";
    $connect->query($sql);
} ?>

试试这个shell脚本

DBENGINE='InnoDB' ;
DBUSER='your_db_user' ;
DBNAME='your_db_name' ;
DBHOST='your_db_host'
DBPASS='your_db_pass' ;
mysqldump --add-drop-table -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME > mtest.sql; mysql -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME -Nse "SHOW TABLES;" | while read TABLE ; do mysql -h$DBHOST -u$DBUSER -p$DBPASS $DBNAME -Nse "ALTER TABLE $TABLE ENGINE=$DBENGINE;" ; done

当表很大时,最好从控制台进行操作

convert-to-innodb.sh

#!/usr/bin/env bash

# Usage: ./convert-to-innodb.sh 'db' 'user' 'password' | mysql 'db' -u  user -p password


set -eu

db="$1"
user="$2"
pass="$3"


sql="SET @DATABASE_NAME = '${db}';"

sql+="SELECT  CONCAT('ALTER TABLE \`', table_name, '\` ENGINE=InnoDB;') AS sql_statements
FROM    information_schema.tables AS tb
WHERE   table_schema = @DATABASE_NAME
AND     \`ENGINE\` = 'MyISAM'
AND     \`TABLE_TYPE\` = 'BASE TABLE'
ORDER BY table_name DESC;"

echo $sql | mysql -u${user} -p${pass} | tail -n +2 

你可以在mysql命令行工具中执行这个语句:

echo "SELECT concat('ALTER TABLE `',TABLE_NAME,'` ENGINE=InnoDB;')
FROM Information_schema.TABLES 
WHERE ENGINE != 'InnoDB' AND TABLE_TYPE='BASE TABLE' 
AND TABLE_SCHEMA='name-of-database'" | mysql > convert.sql

您可能需要指定用户名和密码:mysql -u username -p 结果是一个sql脚本,你可以管道回mysql:

mysql name-of-database < convert.sql

替换上述语句和命令行中的"name-of-database"。

要为所有非系统模式中的所有表生成ALTER语句,按这些模式/表排序,运行以下命令:

SELECT  CONCAT('ALTER TABLE ',TABLE_SCHEMA,'.', table_name, ' ENGINE=InnoDB;') AS sql_statements
FROM    information_schema.tables
WHERE   TABLE_SCHEMA NOT IN ('mysql', 'information_schema', 'performance_schema', 'innodb', 'sys', 'tmp')
AND     `ENGINE` = 'MyISAM'
AND     `TABLE_TYPE` = 'BASE TABLE'
ORDER BY TABLE_SCHEMA, table_name DESC;

之后,通过客户端运行这些查询来执行修改。

答案基于上述答案,但改进了模式处理。