我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。
我想知道是否有一种方法可以快速将它们全部更改为InnoDB?
我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。
我想知道是否有一种方法可以快速将它们全部更改为InnoDB?
当前回答
遵循步骤:
Use MySql commands as follows, for converting to InnoDB (ALTER TABLE t1 ENGINE = InnoDB) or (ALTER TABLE t1 ENGINE = MyISAM) for MyISAM (You should do this for each individual tables, t1 is for the table name.). Write a script that loops on all tables and run the alter command Use an already available script to handle that: https://github.com/rafihaidari/convert-mysql-tables-storage-engine Try this SQL to Get all info will get all the tables information then you can change all the table from isam to InnoDB SELECT CONCAT('ALTER TABLE ',TABLE_NAME,' ENGINE=InnoDB;') FROM INFORMATION_SCHEMA.TABLES WHERE ENGINE='MyISAM' AND table_schema = 'your_DB_Name';
其他回答
创建数据库的SQL转储文件(database_dump.sql),并在记事本中打开它。 将所有“ENGINE=MyISAM”替换为“ENGINE=InnoDB”。 保存文件并将其导入数据库。
<?php
// connect your database here first
//
// Actual code starts here
$sql = "SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'your_database_name'
AND ENGINE = 'MyISAM'";
$rs = mysql_query($sql);
while($row = mysql_fetch_array($rs))
{
$tbl = $row[0];
$sql = "ALTER TABLE `$tbl` ENGINE=INNODB";
mysql_query($sql);
}
?>
<?php
// connect your database here first
mysql_connect('host', 'user', 'pass');
$databases = mysql_query('SHOW databases');
while($db = mysql_fetch_array($databases)) {
echo "database => {$db[0]}\n";
mysql_select_db($db[0]);
$tables = mysql_query('SHOW tables');
while($tbl = mysql_fetch_array($tables)) {
echo "table => {$tbl[0]}\n";
mysql_query("ALTER TABLE {$tbl[0]} ENGINE=InnoDB");
}
}
如果您使用的是Windows,您可以在批处理文件中使用以下循环完成此任务。
set database=YOURDATABASENAME
for /F "tokens=1 skip=1 usebackq" %%a in (`mysql %%database%% -e "show table status where Engine != 'InnoDB';"`) do (
mysql %database% -e "ALTER TABLE %%a ENGINE = 'InnoDB';"
)
只需将YOURDATABASENAME更改为目标数据库的名称,或者使用%~1通过命令行传递数据库名称。
所有当前不是InnoDB的表都将被转换为InnoDB。如果您像问题所建议的那样专门针对MyISAM,下面的代码有一个仅针对MyISAM的更新的MySQL条件。
set database=YOURDATABASENAME
for /F "tokens=1 skip=1 usebackq" %%a in (`mysql %%database%% -e "show table status where Engine = 'MyISAM';"`) do (
mysql %database% -e "ALTER TABLE %%a ENGINE = 'InnoDB';"
)
要为所有非系统模式中的所有表生成ALTER语句,按这些模式/表排序,运行以下命令:
SELECT CONCAT('ALTER TABLE ',TABLE_SCHEMA,'.', table_name, ' ENGINE=InnoDB;') AS sql_statements
FROM information_schema.tables
WHERE TABLE_SCHEMA NOT IN ('mysql', 'information_schema', 'performance_schema', 'innodb', 'sys', 'tmp')
AND `ENGINE` = 'MyISAM'
AND `TABLE_TYPE` = 'BASE TABLE'
ORDER BY TABLE_SCHEMA, table_name DESC;
之后,通过客户端运行这些查询来执行修改。
答案基于上述答案,但改进了模式处理。