运行此SQL语句(在MySQL客户端、phpMyAdmin或任何地方)检索数据库中的所有MyISAM表。

将name_of_your_db变量的值替换为您的数据库名称。

SET @DATABASE_NAME = 'name_of_your_db';

SELECT  CONCAT('ALTER TABLE `', table_name, '` ENGINE=InnoDB;') AS sql_statements
FROM    information_schema.tables AS tb
WHERE   table_schema = @DATABASE_NAME
AND     `ENGINE` = 'MyISAM'
AND     `TABLE_TYPE` = 'BASE TABLE'
ORDER BY table_name DESC;

然后，复制输出并作为一个新的SQL查询运行。

你可以在mysql命令行工具中执行这个语句:

echo "SELECT concat('ALTER TABLE `',TABLE_NAME,'` ENGINE=InnoDB;')
FROM Information_schema.TABLES 
WHERE ENGINE != 'InnoDB' AND TABLE_TYPE='BASE TABLE' 
AND TABLE_SCHEMA='name-of-database'" | mysql > convert.sql

您可能需要指定用户名和密码:mysql -u username -p 结果是一个sql脚本，你可以管道回mysql:

mysql name-of-database < convert.sql

替换上述语句和命令行中的"name-of-database"。

只是测试了另一种(简单的?)方法，对我来说很有效。

只需导出您的DB为.sql文件，编辑它与gedit或记事本;

将ENGINE=MyISAM替换为ENGINE=INNODB并保存已编辑的文件

编号或替换完成应该是你的表的编号

导入到MySQL (phpMyAdmin或命令行)

瞧!

我是一个新手，必须找到自己的解决方案，因为网上的mysql命令通常充满了拼写错误，这对刚开始使用的人来说是一个现实生活的噩梦。这是我的解决方案....

我用excel一次准备了几十个命令(可以复制和粘贴)，而不是每个表一个命令。

How? expand your putty window and enter mysql and then run the command "SHOW TABLE STATUS;" and the copy/paste the output to microsoft excel. Go to the Data tab and use the "text to columns" feature an delimit the columns by a space key. Then Sort the columns by whichever column shows your table types and delete all rows which the tables are already in InnoDb format (because we don't need to run commands against them, they are already done). Then add 2 columns to the left of the tables column, and 2 columns to the right. Then paste in the first part of the command in column-1 (see below). Column 2 should contain only a space. Column 3 is your tables column. Column 4 should contain only a space. Column 5 is the last part of your command. It should look like this:

column-1        column-2            column-3         column-4     column-5
ALTER TABLE     t_lade_tr           ENGINE=InnoDB;
ALTER TABLE     t_foro_detail_ms    ENGINE=InnoDB;
ALTER TABLE     t_ljk_ms            ENGINE=InnoDB;

然后每次复制粘贴5行到mysql中。这将一次转换大约5个。我注意到，如果我一次做了更多的操作，那么命令就会失败。

这是一个简单的php脚本。

<?php
    @error_reporting(E_ALL | E_STRICT);
    @ini_set('display_errors', '1');


    $con = mysql_connect('server', 'user', 'pass');
    $dbName = 'moodle2014';

    $sql = "SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = '".$dbName."';";
    $rs = mysql_query($sql, $con);

    $count = 0;
    $ok = 0;
    while($row = mysql_fetch_array($rs)){
            $count ++;
            $tbl = $row[0];
            $sql = "ALTER TABLE ".$dbName.".".$tbl." ENGINE=INNODB;";
            $resultado = mysql_query($sql);
            if ($resultado){
                    $ok ++;
                    echo $sql."<hr/>";
            }
    }
    if ($count == $ok){
            echo '<div style="color: green"><b>ALL OK</b></div>';
    }else{
            echo '<div style="color: red"><b>ERRORS</b>Total tables: '.$count.', updated tables:'.$ok.'</div>';
    }

<?php

  // connect your database here first

  mysql_connect('host', 'user', 'pass');

  $databases = mysql_query('SHOW databases');

  while($db = mysql_fetch_array($databases)) {
    echo "database => {$db[0]}\n";
    mysql_select_db($db[0]);

    $tables = mysql_query('SHOW tables');

    while($tbl = mysql_fetch_array($tables)) {
      echo "table => {$tbl[0]}\n";
      mysql_query("ALTER TABLE {$tbl[0]} ENGINE=InnoDB");
    }
  }