如果没有UINavigationController,我似乎无法得到最顶端的UIViewController。以下是我目前所掌握的:

UIApplication.sharedApplication().keyWindow?.rootViewController?.presentViewController(vc, animated: true, completion: nil)

然而,它似乎没有做任何事情。keyWindow和rootViewController似乎也不是nil值,所以可选的链接应该不是问题。

注意:这样做不是一个好主意。它打破了MVC模式。


当前回答

class func topViewController(controller: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {
        if let navigationController = controller as? UINavigationController {
            return topViewController(controller: navigationController.visibleViewController)
        }
        if let tabController = controller as? UITabBarController {
            if let selected = tabController.selectedViewController {
                return topViewController(controller: selected)
            }
        }
        if let presented = controller?.presentedViewController {
            return topViewController(controller: presented)
        }
        return controller
    }

其他回答

最简单的方法是从视图控制器堆栈中取出最后一个:

if let viewController: UIViewController = navigationController.viewControllers.last {
    // This `viewController` is on the top.
}

@AlberZou略有变化,使用计算变量而不是函数

extension UIViewController {
  var topMostViewController : UIViewController {

    if let presented = self.presentedViewController {
      return presented.topMostViewController
    }

    if let navigation = self as? UINavigationController {
      return navigation.visibleViewController?.topMostViewController ?? navigation
    }

    if let tab = self as? UITabBarController {
      return tab.selectedViewController?.topMostViewController ?? tab
    }

    return self
  }
}

extension UIApplication {
  var topMostViewController : UIViewController? {
    return self.keyWindow?.rootViewController?.topMostViewController
  }
}

然后说

if let topViewControler = UIApplication.shared.topMostViewController {
    ... do stuff
}

试试这个

let topVisibleVC = UIApplication.shared.keyWindow?.rootViewController?.visibleViewController
    extension UIApplication {
        
       public var mainKeyWindow: UIWindow? {
           if #available(iOS 13, *) {
             return UIApplication.shared.connectedScenes
            .filter { $0.activationState == .foregroundActive }
            .first(where: { $0 is UIWindowScene })
            .flatMap { $0 as? UIWindowScene }?.windows
            .first(where: \.isKeyWindow)
           } else {
              return UIApplication.shared.windows.first { $0.isKeyWindow }
           }
        }
    

    public var rootViewController: UIViewController? {
        guard let keyWindow = UIApplication.shared.mainKeyWindow, let rootViewController = keyWindow.rootViewController else {
            return nil
        }
        return rootViewController
    }

    public func topViewController(controller: UIViewController? = UIApplication.shared.rootViewController) -> UIViewController? {

        if controller == nil {
            return topViewController(controller: rootViewController)
        }
        
        if let navigationController = controller as? UINavigationController {
            return topViewController(controller: navigationController.visibleViewController)
        }

        if let tabController = controller as? UITabBarController {
            if let selectedViewController = tabController.selectedViewController {
                return topViewController(controller: selectedViewController)
            }
        }

        if let presentedViewController = controller?.presentedViewController {
            return topViewController(controller: presentedViewController)
        }

        return controller
    }
}

Swift 5.2及以上版本

太多口味了,但都不是一种反复精心制作的。结合前面的内容:

     func topMostController() -> UIViewController? {
        var from = UIApplication.shared.keyWindow?.rootViewController
        while (from != nil) {
            if let to = (from as? UITabBarController)?.selectedViewController {
                from = to
            } else if let to = (from as? UINavigationController)?.visibleViewController {
                from = to
            } else if let to = from?.presentedViewController {
                from = to
            } else {
                break
            }
        }
        return from
    }