这是基于Gazoris的答案，但URL解码了参数，因此当它们包含除数字和字母以外的数据时可以使用:

function urlParam(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    // Need to decode the URL parameters, including putting in a fix for the plus sign
    // https://stackoverflow.com/a/24417399
    return results ? decodeURIComponent(results[1].replace(/\+/g, '%20')) : null;
}

对Sameer的回答略有改进，将参数缓存为闭包，以避免每次调用时解析和遍历所有参数

var getURLParam = (function() {
    var paramStr = decodeURIComponent(window.location.search).substring(1);
    var paramSegs = paramStr.split('&');
    var params = [];
    for(var i = 0; i < paramSegs.length; i++) {
        var paramSeg = paramSegs[i].split('=');
        params[paramSeg[0]] = paramSeg[1];
    }
    console.log(params);
    return function(key) {
        return params[key];
    }
})();

或者你可以用这个简洁的小函数，因为为什么解这么复杂?

function getQueryParam(param, defaultValue = undefined) {
    location.search.substr(1)
        .split("&")
        .some(function(item) { // returns first occurence and stops
            return item.split("=")[0] == param && (defaultValue = item.split("=")[1], true)
        })
    return defaultValue
}

当简化和联机时看起来更好:

单线解

var queryDict = {};
location.search.substr(1).split("&").forEach(function(item) {queryDict[item.split("=")[0]] = item.split("=")[1]})

result:
queryDict['sent'] // undefined or 'value'

但如果你有编码字符或多值键呢?

你最好看看这个答案:如何在JavaScript中获得查询字符串值?

偷偷高峰

"?a=1&b=2&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> queryDict
a: ["1", "5", "t e x t"]
b: ["2"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]

> queryDict["a"][1] // "5"
> queryDict.a[1] // "5"

还有一个使用URI.js库的例子。

例子准确地回答了所问的问题。

var url = 'http://example.com?sent=yes'; var urlParams = new URI(url).search(true); // 1. Does sent exist? var sendExists = urlParams.sent !== undefined; // 2. Is it equal to "yes"? var sendIsEqualtToYes = urlParams.sent == 'yes'; // output results in readable form // not required for production if (sendExists) { console.log('Url has "sent" param, its value is "' + urlParams.sent + '"'); if (urlParams.sent == 'yes') { console.log('"Sent" param is equal to "yes"'); } else { console.log('"Sent" param is not equal to "yes"'); } } else { console.log('Url hasn\'t "sent" param'); } <script src="https://cdnjs.cloudflare.com/ajax/libs/URI.js/1.18.2/URI.min.js"></script>

我希望使用完整的简单REG Exp

  function getQueryString1(param) {
    return decodeURIComponent(
        (location.search.match(RegExp("[?|&]"+param+'=(.+?)(&|$)'))||[,null])[1]
    );
  }

使用这个

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}