有没有一种方法可以以平台无关的方式确定一台机器有多少个C/ c++内核?如果不存在这样的东西,如何确定每个平台(Windows/*nix/Mac)?
当前回答
与c++无关,但在Linux上我通常这样做:
grep processor /proc/cpuinfo | wc -l
适用于bash/perl/python/ruby等脚本语言。
其他回答
Note that "number of cores" might not be a particularly useful number, you might have to qualify it a bit more. How do you want to count multi-threaded CPUs such as Intel HT, IBM Power5 and Power6, and most famously, Sun's Niagara/UltraSparc T1 and T2? Or even more interesting, the MIPS 1004k with its two levels of hardware threading (supervisor AND user-level)... Not to mention what happens when you move into hypervisor-supported systems where the hardware might have tens of CPUs but your particular OS only sees a few.
最好的情况是告诉您在本地OS分区中拥有的逻辑处理单元的数量。除非您是管理程序,否则不要考虑看到真正的机器。今天这个规则唯一的例外是在x86领域,但非虚拟机的末日很快就会到来……
你也可以在。net中使用WMI,但这样你就依赖于WMI服务的运行 等。有时它在本地工作,但当相同的代码在服务器上运行时就会失败。 我认为这是一个名称空间问题,与您正在读取其值的“名称”有关。
这个功能是c++ 11标准的一部分。
#include <thread>
unsigned int nthreads = std::thread::hardware_concurrency();
对于较老的编译器,可以使用Boost。线程库。
#include <boost/thread.hpp>
unsigned int nthreads = boost::thread::hardware_concurrency();
在任何一种情况下,hardware_concurrency()都会根据CPU内核和超线程单元的数量返回硬件能够并发执行的线程数。
Windows Server 2003及以后版本允许您利用GetLogicalProcessorInformation函数
http://msdn.microsoft.com/en-us/library/ms683194.aspx
在Linux上,使用_SC_NPROCESSORS_ONLN可能是不安全的,因为它不是POSIX标准的一部分,sysconf手册也有同样的说明。所以有可能_SC_NPROCESSORS_ONLN不存在:
These values also exist, but may not be standard.
[...]
- _SC_NPROCESSORS_CONF
The number of processors configured.
- _SC_NPROCESSORS_ONLN
The number of processors currently online (available).
一个简单的方法是读取/proc/stat或/proc/cpuinfo并计算它们:
#include<unistd.h>
#include<stdio.h>
int main(void)
{
char str[256];
int procCount = -1; // to offset for the first entry
FILE *fp;
if( (fp = fopen("/proc/stat", "r")) )
{
while(fgets(str, sizeof str, fp))
if( !memcmp(str, "cpu", 3) ) procCount++;
}
if ( procCount == -1)
{
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}
printf("Proc Count:%d\n", procCount);
return 0;
}
使用 /proc/cpuinfo:
#include<unistd.h>
#include<stdio.h>
int main(void)
{
char str[256];
int procCount = 0;
FILE *fp;
if( (fp = fopen("/proc/cpuinfo", "r")) )
{
while(fgets(str, sizeof str, fp))
if( !memcmp(str, "processor", 9) ) procCount++;
}
if ( !procCount )
{
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}
printf("Proc Count:%d\n", procCount);
return 0;
}
同样的方法在shell中使用grep:
grep -c ^processor /proc/cpuinfo
Or
grep -c ^cpu /proc/stat # subtract 1 from the result