我有一个String[],其值如下:

public static final String[] VALUES = new String[] {"AB","BC","CD","AE"};

给定字符串s,是否有一种测试VALUES是否包含s的好方法?


当前回答

Arrays.asList(yourArray).contains(yourValue)

警告:这对基元数组无效(请参见注释)。


从java-8开始,您现在可以使用Streams。

String[] values = {"AB","BC","CD","AE"};
boolean contains = Arrays.stream(values).anyMatch("s"::equals);

要检查int、double或long数组是否包含值,请分别使用IntStream、DoubleStream或LongStream。

实例

int[] a = {1,2,3,4};
boolean contains = IntStream.of(a).anyMatch(x -> x == 4);

其他回答

使用以下方法(在本代码中contains()方法是ArrayUtils.in()):

对象Utils.java

public class ObjectUtils {
    /**
     * A null safe method to detect if two objects are equal.
     * @param object1
     * @param object2
     * @return true if either both objects are null, or equal, else returns false.
     */
    public static boolean equals(Object object1, Object object2) {
        return object1 == null ? object2 == null : object1.equals(object2);
    }
}

阵列应用程序.java

public class ArrayUtils {
    /**
     * Find the index of of an object is in given array,
     * starting from given inclusive index.
     * @param ts    Array to be searched in.
     * @param t     Object to be searched.
     * @param start The index from where the search must start.
     * @return Index of the given object in the array if it is there, else -1.
     */
    public static <T> int indexOf(final T[] ts, final T t, int start) {
        for (int i = start; i < ts.length; ++i)
            if (ObjectUtils.equals(ts[i], t))
                return i;
        return -1;
    }

    /**
     * Find the index of of an object is in given array, starting from 0;
     * @param ts Array to be searched in.
     * @param t  Object to be searched.
     * @return indexOf(ts, t, 0)
     */
    public static <T> int indexOf(final T[] ts, final T t) {
        return indexOf(ts, t, 0);
    }

    /**
     * Detect if the given object is in the given array.
     * @param ts Array to be searched in.
     * @param t  Object to be searched.
     * @return If indexOf(ts, t) is greater than -1.
     */
    public static <T> boolean in(final T[] ts, final T t) {
        return indexOf(ts, t) > -1;
    }
}

正如您在上面的代码中看到的,还有其他实用方法ObjectUtils.equals()和ArrayUtils.indexOf(),它们也在其他地方使用。

使用Java 8,您可以创建一个流,并检查流中的任何条目是否与“s”匹配:

String[] values = {"AB","BC","CD","AE"};
boolean sInArray = Arrays.stream(values).anyMatch("s"::equals);

或作为通用方法:

public static <T> boolean arrayContains(T[] array, T value) {
    return Arrays.stream(array).anyMatch(value::equals);
}

如果数组未排序,则必须遍历所有内容,并对每个内容调用equals。

如果数组已排序,则可以执行二进制搜索,Arrays类中有一个。

一般来说,如果要进行大量的成员身份检查,您可能希望将所有内容存储在集合中,而不是存储在数组中。

最短解数组VALUES可能包含重复项自Java 9以来

List.of(VALUES).contains(s);

试试看:

ArrayList<Integer> arrlist = new ArrayList<Integer>(8);

// use add() method to add elements in the list
arrlist.add(20);
arrlist.add(25);
arrlist.add(10);
arrlist.add(15);

boolean retval = arrlist.contains(10);
if (retval == true) {
    System.out.println("10 is contained in the list");
}
else {
    System.out.println("10 is not contained in the list");
}