我想要一个Java程序来计算两个日期之间的天数。

输入第一个日期(德语表示法;有空格:"dd mm yyyy") 输入第二个日期。 程序应该计算两个日期之间的天数。

我怎样才能把闰年和夏天时包括进来呢?

我的代码:

import java.util.Calendar;
import java.util.Date;
import java.util.Scanner;

public class NewDateDifference {

    public static void main(String[] args) {

        System.out.print("Insert first date: ");
        Scanner s = new Scanner(System.in);
        String[] eingabe1 = new String[3];

        while (s.hasNext()) {
            int i = 0;
            insert1[i] = s.next();
            if (!s.hasNext()) {
                s.close();
                break;
            }
            i++;
        }

        System.out.print("Insert second date: ");
        Scanner t = new Scanner(System.in);
        String[] insert2 = new String[3];

        while (t.hasNext()) {
            int i = 0;
            insert2[i] = t.next();
            if (!t.hasNext()) {
                t.close();
                break;
            }
            i++;
        }

        Calendar cal = Calendar.getInstance();

        cal.set(Calendar.DAY_OF_MONTH, Integer.parseInt(insert1[0]));
        cal.set(Calendar.MONTH, Integer.parseInt(insert1[1]));
        cal.set(Calendar.YEAR, Integer.parseInt(insert1[2]));
        Date firstDate = cal.getTime();

        cal.set(Calendar.DAY_OF_MONTH, Integer.parseInt(insert2[0]));
        cal.set(Calendar.MONTH, Integer.parseInt(insert2[1]));
        cal.set(Calendar.YEAR, Integer.parseInt(insert2[2]));
        Date secondDate = cal.getTime();


        long diff = secondDate.getTime() - firstDate.getTime();

        System.out.println ("Days: " + diff / 1000 / 60 / 60 / 24);
    }
}

当前回答

下面的方法非常适合我:

public int daysBetween(LocalDate later, LocalDate before) {
        SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
        int daysBetween = 0;
        try {
            Date dateBefore = myFormat.parse(localDateToString(before));
            Date dateAfter = myFormat.parse(localDateToString(later));
            long difference = dateAfter.getTime() - dateBefore.getTime();
            daysBetween = (int) (difference / (1000 * 60 * 60 * 24));
        } catch (Exception e) {
            e.printStackTrace();
        }
        return daysBetween;
    }

    public String localDateToString(LocalDate date) {
        DateTimeFormatter myFormat = DateTimeFormatter.ofPattern("dd MM yyyy");
        return date.format(myFormat).toString();
    }

其他回答

当我运行你的程序时,它连我都找不到 直到我可以开始第二次约会。

这样更简单,更不容易出错。

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.text.SimpleDateFormat;
import java.util.Date;

public class Test001 {

    public static void main(String[] args) throws Exception {

        BufferedReader br = null;

        br = new BufferedReader(new InputStreamReader(System.in));
        SimpleDateFormat sdf = new SimpleDateFormat("dd MM yyyy");

        System.out.println("Insert first date : ");
        Date dt1 = sdf.parse(br.readLine().trim());

        System.out.println("Insert second date : ");
        Date dt2 = sdf.parse(br.readLine().trim());

        long diff = dt2.getTime() - dt1.getTime();

        System.out.println("Days: " + diff / 1000L / 60L / 60L / 24L);

        if (br != null) {
            br.close();
        }
    }
}

我们可以利用LocalDate和ChronoUnit java库,下面的代码工作正常。 Date的格式为yyyy-MM-dd。

import java.time.LocalDate;
import java.time.temporal.ChronoUnit;
import java.util.*;
class Solution {
    public int daysBetweenDates(String date1, String date2) {
        LocalDate dt1 = LocalDate.parse(date1);
        LocalDate dt2= LocalDate.parse(date2);

        long diffDays = ChronoUnit.DAYS.between(dt1, dt2);

        return Math.abs((int)diffDays);
    }
}

Java日期库是出了名的坏。我建议使用Joda Time。它会为你照顾闰年、时区等。

最小工作示例:

import java.util.Scanner;
import org.joda.time.DateTime;
import org.joda.time.Days;
import org.joda.time.LocalDate;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;

public class DateTestCase {

    public static void main(String[] args) {

        System.out.print("Insert first date: ");
        Scanner s = new Scanner(System.in);
        String firstdate = s.nextLine();
        System.out.print("Insert second date: ");
        String seconddate = s.nextLine();

        // Formatter
        DateTimeFormatter dateStringFormat = DateTimeFormat
                .forPattern("dd MM yyyy");
        DateTime firstTime = dateStringFormat.parseDateTime(firstdate);
        DateTime secondTime = dateStringFormat.parseDateTime(seconddate);
        int days = Days.daysBetween(new LocalDate(firstTime),
                                    new LocalDate(secondTime)).getDays();
        System.out.println("Days between the two dates " + days);
    }
}

更新:2013年的原始答案现在已经过时,因为一些类已经被替换了。新的方法是使用新的java。时间类。

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("dd MM yyyy");
String inputString1 = "23 01 1997";
String inputString2 = "27 04 1997";

try {
    LocalDateTime date1 = LocalDate.parse(inputString1, dtf);
    LocalDateTime date2 = LocalDate.parse(inputString2, dtf);
    long daysBetween = Duration.between(date1, date2).toDays();
    System.out.println ("Days: " + daysBetween);
} catch (ParseException e) {
    e.printStackTrace();
}

注意,这个解决方案给出的是实际的24小时天数,而不是日历天数。对于后者,请使用

long daysBetween = ChronoUnit.DAYS.between(date1, date2)

原始答案(Java 8已过时)

您正在使用字符串进行一些不必要的转换。有一个SimpleDateFormat类-试试这个:

SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
String inputString1 = "23 01 1997";
String inputString2 = "27 04 1997";

try {
    Date date1 = myFormat.parse(inputString1);
    Date date2 = myFormat.parse(inputString2);
    long diff = date2.getTime() - date1.getTime();
    System.out.println ("Days: " + TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS));
} catch (ParseException e) {
    e.printStackTrace();
}

编辑:由于有一些关于这段代码正确性的讨论:它确实考虑到了闰年。然而,TimeUnit.DAYS.convert函数失去了精度,因为毫秒被转换为天(更多信息请参阅链接文档)。如果这是一个问题,diff也可以手动转换:

float days = (diff / (1000*60*60*24));

注意,这是一个浮点值,不一定是整型。

Use:

public int getDifferenceDays(Date d1, Date d2) {
    int daysdiff = 0;
    long diff = d2.getTime() - d1.getTime();
    long diffDays = diff / (24 * 60 * 60 * 1000) + 1;
    daysdiff = (int) diffDays;
    return daysdiff;
}