我有几个方法返回不同的泛型列表。

在。net中存在任何类静态方法或将任何列表转换为数据表?我唯一能想到的是使用反射来做到这一点。

如果我有这个:

List<Whatever> whatever = new List<Whatever>();

(这下代码当然不工作,但我想有这样的可能性:

DataTable dt = (DataTable) whatever;

当前回答

如果你想使用反射并设置列的顺序/只包括一些列/排除一些列,试试这个:

        private static DataTable ConvertToDataTable<T>(IList<T> data, string[] fieldsToInclude = null,
string[] fieldsToExclude = null)
    {
        PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(typeof(T));
        DataTable table = new DataTable();
        foreach (PropertyDescriptor prop in properties)
        {
            if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
                (fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
                continue;
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
        }

        foreach (T item in data)
        {
            var atLeastOnePropertyExists = false;
            DataRow row = table.NewRow();
            foreach (PropertyDescriptor prop in properties)
            {

                if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
                    continue;

                row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
                atLeastOnePropertyExists = true;
            }

            if(atLeastOnePropertyExists) table.Rows.Add(row);
        }


        if (fieldsToInclude != null)
            SetColumnsOrder(table, fieldsToInclude);

        return table;

    }

    private static void SetColumnsOrder(DataTable table, params String[] columnNames)
    {
        int columnIndex = 0;
        foreach (var columnName in columnNames)
        {
            table.Columns[columnName].SetOrdinal(columnIndex);
            columnIndex++;
        }
    }

其他回答

MSDN上的这个链接值得一看:如何:实现CopyToDataTable<T>,其中泛型类型T不是一个数据流

这增加了一个扩展方法,让你这样做:

// Create a sequence. 
Item[] items = new Item[] 
{ new Book{Id = 1, Price = 13.50, Genre = "Comedy", Author = "Gustavo Achong"}, 
  new Book{Id = 2, Price = 8.50, Genre = "Drama", Author = "Jessie Zeng"},
  new Movie{Id = 1, Price = 22.99, Genre = "Comedy", Director = "Marissa Barnes"},
  new Movie{Id = 1, Price = 13.40, Genre = "Action", Director = "Emmanuel Fernandez"}};

// Query for items with price greater than 9.99.
var query = from i in items
             where i.Price > 9.99
             orderby i.Price
             select i;

// Load the query results into new DataTable.
DataTable table = query.CopyToDataTable();

2019年的答案,如果你正在使用。net Core——使用Nuget ToDataTable库。优点:

性能优于FastMember 还可以创建结构化的SqlParameters作为SQL Server表值参数

免责声明-我是ToDataTable的作者

性能——我扩展了一些Benchmark . net测试,并将它们包含在ToDataTable repo中。结果如下:

创建100,000行数据表:

                           MacOS         Windows
Reflection                 818.5 ms      818.3 ms
FastMember from           1105.5 ms      976.4 ms
 Mark's answer
Improved FastMember        524.6 ms      456.4 ms
ToDataTable                449.0 ms      376.5 ms

Marc回答中建议的FastMember方法的性能似乎比Mary使用反射的回答差,但我使用FastMember TypeAccessor滚动了另一个方法,它的性能要好得多。尽管如此,ToDataTable包的性能还是优于其他包。

我认为它更方便和容易使用。

   List<Whatever> _lobj= new List<Whatever>(); 
    var json = JsonConvert.SerializeObject(_lobj);
                DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));

要将泛型列表转换为数据表,可以使用DataTableGenerator

这个库允许您将列表转换为具有多种功能的数据表,如

翻译数据表头 指定要显示的列

  private DataTable CreateDataTable(IList<T> item)
        {
            Type type = typeof(T);
            var properties = type.GetProperties();

            DataTable dataTable = new DataTable();
            foreach (PropertyInfo info in properties)
            {
                dataTable.Columns.Add(new DataColumn(info.Name, Nullable.GetUnderlyingType(info.PropertyType) ?? info.PropertyType));
            }

            foreach (T entity in item)
            {
                object[] values = new object[properties.Length];
                for (int i = 0; i < properties.Length; i++)
                {
                    values[i] = properties[i].GetValue(entity);
                }

                dataTable.Rows.Add(values);
            }
            return dataTable;
        }